1948 United States presidential election in Illinois
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All 28 Illinois votes to the Electoral College | ||||||||||||||||||||||||||
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| Elections in Illinois |
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The 1948 United States presidential election in Illinois took place on November 2, 1948, as part of the 1948 United States presidential election. Illinois voters chose twenty-eight[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
Illinois was won by incumbent President Harry S. Truman (D–Missouri), running with Senator Alben W. Barkley, with 50.07% of the popular vote, against Governor Thomas Dewey (R–New York), running with Governor Earl Warren, with 49.22% of the popular vote.[3][4]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Harry S. Truman (inc.) | 1,994,715 | 50.07% | |
| Republican | Thomas Dewey | 1,961,103 | 49.22% | |
| Prohibition | Claude A. Watson | 11,959 | 0.30% | |
| Socialist | Norman Thomas | 11,522 | 0.29% | |
| Write-in | 4,747 | 0.12% | ||
| Total votes | 3,984,046 | 100% | ||
References
- ^ "United States Presidential election of 1948 - Encyclopædia Britannica". Retrieved October 26, 2017.
- ^ "1948 Election for the Forty-First Term (1949-53)". Retrieved October 26, 2017.
- ^ "1948 Presidential General Election Results - Illinois". Retrieved October 26, 2017.
- ^ "The American Presidency Project - Election of 1948". Retrieved October 26, 2017.
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