1852 United States presidential election in Ohio
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Elections in Ohio |
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The 1852 United States presidential election in Ohio was held on November 2, 1852. Ohio voters chose twenty-three electors to the Electoral College, who voted for President and Vice President.
The Democratic Party candidate, Franklin Pierce, won the state of Ohio with 47.83% of the popular vote. The Whig Party candidate, Winfield Scott, garnered 43.18% of the popular vote.[1]
Results
United States presidential election in Ohio, 1852 | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
style="background-color:Template:Democratic Party (United States)/meta/color; width: 3px" | | Democratic | Franklin Pierce | 168,933 | 47.83% | 23 |
style="background-color:Template:Whig Party (United States)/meta/color; width: 3px" | | Whig | Winfield Scott | 152,523 | 43.18% | 0 |
style="background-color:Template:Free Soil Party/meta/color; width: 3px" | | Free Soil | John P. Hale | 31,732 | 8.98% | 0 |
Totals | 353,188 | 100.0% | 23 |