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1852 United States presidential election in Ohio

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United States presidential election, 1852

← 1848 November 2, 1852 1856 →
 
Nominee Franklin Pierce Winfield Scott John P. Hale
Party Democratic Whig Free Soil
Home state New Hampshire New Jersey New Hampshire
Running mate William R. King William A. Graham George Washington Julian
Electoral vote 23 0 0
Popular vote 168,933 152,523 31,732
Percentage 47.83% 43.18% 8.98%

President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

The 1852 United States presidential election in Ohio was held on November 2, 1852. Ohio voters chose twenty-three electors to the Electoral College, who voted for President and Vice President.

The Democratic Party candidate, Franklin Pierce, won the state of Ohio with 47.83% of the popular vote. The Whig Party candidate, Winfield Scott, garnered 43.18% of the popular vote.[1]

Results

United States presidential election in Ohio, 1852
Party Candidate Votes Percentage Electoral votes
style="background-color:Template:Democratic Party (United States)/meta/color; width: 3px" | Democratic Franklin Pierce 168,933 47.83% 23
style="background-color:Template:Whig Party (United States)/meta/color; width: 3px" | Whig Winfield Scott 152,523 43.18% 0
style="background-color:Template:Free Soil Party/meta/color; width: 3px" | Free Soil John P. Hale 31,732 8.98% 0
Totals 353,188 100.0% 23

References