United States presidential election in Virginia, 1992

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United States presidential election in Virginia, 1992
← 1988 November 3, 1992 1996 →
  43 George H.W. Bush 3x4.jpg 44 Bill Clinton 3x4.jpg RossPerotColor.jpg
Nominee George H.W. Bush Bill Clinton Ross Perot
Party Republican Democratic Independent
Home state Texas Arkansas Texas
Running mate Dan Quayle Al Gore James Stockdale
Electoral vote 13 0 0
Popular vote 1,150,517 1,038,650 348,639
Percentage 45.0% 40.6% 13.6%

County Results

President before election

George H. W. Bush

Elected President

Bill Clinton

The 1992 United States presidential election in Virginia took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose thirteen representatives, or electors to the Electoral College, who voted for President and Vice President.

Virginia was won by incumbent President George H.W. Bush (R-Texas) with 44.97% of the popular vote over Governor Bill Clinton (D-Arkansas) with 40.59%. Businessman Ross Perot (I-Texas) finished in third with 13.63% of the popular vote.[1] Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot.[2]


United States presidential election in Virginia, 1992[1][3]
Party Candidate Votes Percentage Electoral votes
Republican George H.W. Bush (inc.) 1,150,517 44.97% 13
Democratic Bill Clinton 1,038,650 40.59% 0
Independent Ross Perot 348,639 13.63% 0
Democrats for Economic Recovery Lyndon LaRouche 11,937 0.47% 0
Libertarian Andre Marrou 5,730 0.22% 0
New Alliance Party Lenora Fulani 3,192 0.12% 0
Totals 2,558,665 100.0% 13