1904 United States presidential election in Nebraska
Appearance
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Elections in Nebraska |
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Government |
The 1904 United States presidential election in Nebraska took place on November 8, 1904. All contemporary 45 states were part of the 1904 United States presidential election. Nebraska voters chose eight electors to the Electoral College, which selected the president and vice president.
Nebraska was won by the Republican nominees, incumbent President Theodore Roosevelt of New York and his running mate Charles W. Fairbanks of Indiana.
Results
United States presidential election in Nebraska, 1904[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | Theodore Roosevelt | 138,558 | 61.38% | 8 | |
Democratic | Alton B. Parker | 52,921 | 23.44% | 0 | |
Populist | Thomas E. Watson | 20,518 | 9.09% | 0 | |
Social Democratic | Eugene Debs | 7,412 | 3.28% | 0 | |
Prohibition | Silas C. Swallow | 6,323 | 2.80% | 0 | |
Totals | 225,732 | 100.00% | 8 | ||
Voter turnout | — |
References
- ^ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Nebraska