United States presidential election in Mississippi, 1992
|Elections in Mississippi|
The 1992 United States presidential election in Mississippi took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
Mississippi was won by incumbent President George H.W. Bush (R-Texas) with 49.68% of the popular vote over Governor Bill Clinton (D-Arkansas) with 40.77%. Businessman Ross Perot (I-Texas) finished in third with 8.72% of the popular vote. Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot.
|United States presidential election in Mississippi, 1992|
|Republican||George H.W. Bush (incumbent)||487,793||49.68%||7|
|New Alliance Party||Lenora Fulani||2,625||0.27%||0|
|Constitution Party||Howard Phillips||1,652||0.17%||0|
|Natural Law||John Hagelin||1,140||0.12%||0|
|Populist||James "Bo" Gritz||545||0.06%||0|
- "1992 Presidential General Election Results - Mississippi". U.S. Election Atlas. Retrieved 8 June 2012.
- "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved 8 June 2012.