Buckeye–Woodhill
(Redirected from Woodland Hills, Cleveland)
Buckeye–Woodhill | |
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.jpg) Buckeye–Woodhill RTA station | |
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| Coordinates: 41°28′53″N 81°36′41″W / 41.4813889°N 81.6113889°W | |
| Country | United States |
| State | Ohio |
| County | Cuyahoga County |
| City | Cleveland |
| Population | |
| • Total | 5,984 |
| Demographics[1] | |
| • White | 5.3% |
| • Black | 92.2% |
| • Hispanic (of any race) | 1.1% |
| • Asian and Pacific Islander | 0.1% |
| • Mixed and Other | 2.4% |
| Time zone | UTC-5 (EST) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP Codes | 44104 |
| Area code | 216 |
| Median income[1] | $18,185 |
| Source: 2020 U.S. Census | |
Buckeye–Woodhill is a neighborhood on the East Side of Cleveland, Ohio. It borders the neighborhoods of University Circle and Fairfax to the north, Kinsman to the west, Buckeye–Shaker to the east, and Mount Pleasant to the south. Once a predominantly Hungarian neighborhood, its population is today largely African American.[2] Formerly known as Woodland Hills, it is politically part of Cleveland's Ward 6.[3]
References
[edit]- ^ a b c "Cleveland Neighborhoods and Wards: Buckeye–Woodhill Neighborhood Factsheet (2021)" (PDF). The Center for Community Solutions (Cleveland). Retrieved June 3, 2022.
- ^ "Buckeye–Woodhill". The Encyclopedia of Cleveland History. Case Western Reserve University. Retrieved June 25, 2020.
- ^ "Current Cleveland City Wards". Northern Ohio Data and Information Service (NODIS), Levin College of Urban Affairs (Cleveland State University). Retrieved June 25, 2020.
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