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::Postage to and from Australia is very delayed at the moment due to limited international flights, so if you are in the USA, buy from USA. [[User:Graeme Bartlett|Graeme Bartlett]] ([[User talk:Graeme Bartlett|talk]]) 23:56, 29 April 2020 (UTC)
::Postage to and from Australia is very delayed at the moment due to limited international flights, so if you are in the USA, buy from USA. [[User:Graeme Bartlett|Graeme Bartlett]] ([[User talk:Graeme Bartlett|talk]]) 23:56, 29 April 2020 (UTC)
:To import plants or seeds from abroad you need a phytosanitary certificate or a [https://www.aphis.usda.gov/aphis/ourfocus/planthealth/import-information/permits/plants-and-plant-products-permits/plants-for-planting/CT_Smalllots_seed small lots permit], to make sure you are not bringing non-native pests or pathogens into the US. Please check USDA APHIS website for what documentation is necessary in your case, and how to apply for it properly. Best regards, [[User:Dr Dima|Dr Dima]] ([[User talk:Dr Dima|talk]]) 06:19, 30 April 2020 (UTC)
:To import plants or seeds from abroad you need a phytosanitary certificate or a [https://www.aphis.usda.gov/aphis/ourfocus/planthealth/import-information/permits/plants-and-plant-products-permits/plants-for-planting/CT_Smalllots_seed small lots permit], to make sure you are not bringing non-native pests or pathogens into the US. Please check USDA APHIS website for what documentation is necessary in your case, and how to apply for it properly. Best regards, [[User:Dr Dima|Dr Dima]] ([[User talk:Dr Dima|talk]]) 06:19, 30 April 2020 (UTC)

== Coronavirus transmission ==

Does a comprehensive test, track, trace strategy in relaxing aspects of lockdowns get cases to 0 or as close as possible to it or does relaxing some restrictions come with the trade off of accepting some level of transmission? [[Special:Contributions/90.192.122.95|90.192.122.95]] ([[User talk:90.192.122.95|talk]]) 20:59, 29 April 2020 (UTC)
:You will have to add isolate to the measures, so that once you detect a case or a contact of a case you can stop transmission. Unless you can test 100% of the population, you will not be sure that there are no cases being transmitted (perhaps assymptomatically). These preventative measures can make the rate trend towards zero, by making [[R zero]] less than 1. If you are very sure that all cases are identified and isolated you should be able to hit zero very fast. But isolation will mean no one living together, no new babies, no migration or movement to or from care facilities. So in your suggestions, it would be a trade off, as total detection and isolation is not possible. UK is a long way from getting to zero. [[User:Graeme Bartlett|Graeme Bartlett]] ([[User talk:Graeme Bartlett|talk]]) 23:54, 29 April 2020 (UTC)


= April 30 =
= April 30 =

Revision as of 12:34, 30 April 2020

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April 23

Could Covid-19 have spread at multiple points from animals to humans?

If it is true that most of the early cases came from a single wildlife market, then one or more of the animals could have been infected prior to being shipped to the market. This would imply that the farmers or others handling the same animal(s) earlier could also have presumably been able to catch the virus.

So why are the earlier cases that were not linked directly to the market assumed to be evidence against zoonotic transmission at the market, rather than as evidence that there might have been an "animal super-spreader" of some kind, or simply that the same animal infected a handful of people handling it, and then was subsequently delivered to the market and spread the virus around at that market?

2600:8806:3400:3DB:793B:C7CF:650:5F5A (talk) 02:31, 23 April 2020 (UTC)Nightvid[reply]

My understanding is that the earlier cases and growing evidence against zoonotic transmission occurring at the meat market is because the genetic analysis indicates the possibility that the transfer occurred hundreds of miles away from Wuhan. I'm not sure what you mean by an "animal super-spreader." While it is possible that a single animal or group of animals transferred the virus to more than one person, I'm not sure that's relevant to the issue of the meat market. Basically, the genetic analysis shows 3 main subtypes, each splitting from the previous, i.e. subtype A is the root subtype emerging at or immediately after the zoonotic transfer. At some point, subtype B split off from subtype A, and then substype C split off from subtype B. The viral isolates from Wuhan are subtype B, which indicates that the zoonotic transfer event may not have occurred in Wuhan. Subtype A has been found in Guangdong province, which is 500 miles away from Wuhan, as well as in North America. What this seems to suggest is that the zoonotic transfer event could have happened earlier than we thought, and in southern China, and spread from there. At some point, subtype B mutated off of subtype A, and early on in its spread to Wuhan, mutated into subtype B, which dominated that outbreak. Independently, someone also carried subtype A to North America, which dominated the North American outbreak. Subtype C, at some point, mutated from subtype B, and is what was the type in the outbreak in Europe, as well as other areas of East Asia, but is otherwise largely absent from China.
So, it isn't just that earlier outbreaks occurred, and thus we don't think one animal could have caused both the earlier outbreaks and then the later one in Wuhan (and the wet meat market). Rather, the genetic analysis indicates that the outbreak in Wuhan was a product of human-to-human transmission already occurring, as it was a daughter type to that of the earlier zoonotic transfer event outside of Wuhan. --OuroborosCobra (talk) 02:50, 23 April 2020 (UTC)[reply]
Separate from your main point/reply to the question but this bioRxiv preprint suggests the subtype prevalent in New York is closer to the Italian one than the more common "endogenous" US one although they're relying on a marker to identify the subtypes [1] Nil Einne (talk) 18:25, 23 April 2020 (UTC)[reply]
As we can read here: "The gene for the spike protein in SARS-CoV-2 has an insertion of 12 genetic letters: ccucggcgggca. This mutation may help the spikes bind tightly to human cells — a crucial step in its evolution from a virus that infected bats and other species." This means that before this mutation arose, there would have had to be infections with the virus with humans that then didn't cause an epidemic. The virus may not have been able to cause much of a disease in humans. But one can estimate what the probability of the insertion of the code "ccucggcgggca" and then deduce if this is so low that it would have had to happen in smaller steps. If so, then that would imply that virus was moving back and forth from the animal host to humans a long time before it had the capability of causing an epidemic in humans. Count Iblis (talk) 10:18, 24 April 2020 (UTC)[reply]

Cats vs. dogs cleanliness

I am looking for non-biased scientific information about the cleanliness of cats vs. dogs. I do not want any information from religious sources. For example, Islam does see cats as ritually cleaner than dogs. However, I want to find secular information about cats vs. dogs studied by scientists. Where can I find information about the cleanliness and diseases of these animals online? Thank you. WJetChao (talk) 09:39, 23 April 2020 (UTC)[reply]

Cat Cleanliness vs. Dogs. DroneB (talk) 11:01, 23 April 2020 (UTC)[reply]
  • Cleanliness is not a scientific term, therefore your question cannot be answered using scientific sources, as you wanted. You'll have to define cleanliness. Fgf10 (talk) 12:35, 23 April 2020 (UTC)[reply]
    Can't we measure their respective distances to godliness?
    "Cleanliness" might not be a scientific term, but its a concept that could be defined in such a way that it could be scientifically investigated. I don't have any answers, but I don't think the question should be dismissed like that. Iapetus (talk) 08:45, 24 April 2020 (UTC)[reply]
There's no doubt it could be. But it hasn't been by the OP so far, so my statement about this particular question is completely correct. Fgf10 (talk) 15:09, 24 April 2020 (UTC)[reply]
  • It doesn't take a rocket scientist to observe that cats tend to be more fastidious than dogs. That doesn't necessarily mean you want them walking on your dinner table, though. ←Baseball Bugs What's up, Doc? carrots13:30, 23 April 2020 (UTC)[reply]
  • Having had both cats and dogs, one very observable difference is that cats groom their coats, while dogs don't. Also, dogs like a playful rough-and-tumble with other dogs – which they make clear by inviting their playmates by vocalizing “rough! rough!”. This may get them pretty dirty. Adult cats may fight each other, but then it is not a play fight. If they have gotten dirty, most dogs will not mind getting a good wash, but many cats will resist vehemently. All this is strictly anecdotal and non-scientific. One could define a cleanliness measure by determining how much dirt can be collected from an animal's body, but how to define the population from which samples are taken? Should feral cats and dogs be included? Is it reasonable to compare dogs that go outside with cats that are kept indoors? And should the measure be absolute (in which case a St. Bernard will prove more dirty than a chihuahua) or relative to the animal‘s surface area? And are we really interested in just dirt? What about the shedding of hair? And so on. I doubt a scientist would undertake such a study in the face of such issues, unless there was an urgent need for an answer to some question – in which case the reason for the urgency would probably determine the operationalization of the concept.  --Lambiam 15:00, 23 April 2020 (UTC)[reply]
It has long intrigued me that we regard the cat behaviour of licking themselves all over as a sign of cleanliness. That wouldn't be the case if I did it. Probably more likely to be seen a sign of extreme weirdness and yuckiness. HiLo48 (talk) 18:53, 23 April 2020 (UTC)[reply]
We see it that way because it is actually part of their grooming/cleanliness practice, and if they don't do it, they don't get clean. Similarly, we wouldn't think of it as super clean to pick parasites out of each others hair, but certainly a lot of other primates would view that as part of keeping clean. For cats, part of why their tongue has evolved those backwards facing barbs is for the purpose of use in cleaning themselves. If you licked yourself that way, you don't have backwards barbs on your tongue, so you wouldn't effectively clean anything. --OuroborosCobra (talk) 18:57, 23 April 2020 (UTC)[reply]

CNBC reports air pollution drops by 180%

On April 23, an article on pollution during coronavirus situation said fine particle pollution in Manila went down by 180%. This might be an error. Or could it be theresult of calculating percent change as 100*(new amount-old amount)/(new amount), instead of 100*(new amt- old amount)/(old amt)? If that’s what it is, is this calculation standard, or becoming more common? Is it a more useful way to measure things?Rich (talk) 18:30, 23 April 2020 (UTC)[reply]

This teacher of Mathematics says it's utter nonsense. HiLo48 (talk) 18:36, 23 April 2020 (UTC)[reply]
Can you link to the article in question so we can look it over ourselves? --Jayron32 18:52, 23 April 2020 (UTC)[reply]
Here are two news articles giving the 180% figure: [2], [3]. The last one references a press release by the Environmental Pollution Studies Laboratory of the Institute of Environmental Science & Meteorology at the University of the Philippines.  --Lambiam 19:15, 23 April 2020 (UTC)[reply]
Let's for a moment assume they did mean 100*(new amount-old amount)/(new amount). Let us calculate. Put for brevity x for the old amount and y for the new amount. Then we get
180      =   100 (yx) / y
180 y   =   100 y − 100 x
  80 y   =             − 100 x
       y   =            − 1.25 x.
Negative air pollution! Probably from burning negative oil. This article reports a decrease from the typical Thursday peak value of 38 μg/m3 to 7.1 μg/m3, which is a decrease by 81%. Probably, 180% was a typo for a rounded 80%.  --Lambiam 19:10, 23 April 2020 (UTC)[reply]
Yes but people typically will say there is a “50% off sale”, meaning the 50% is negative. So if -180%=100(y-x)/y, then -1.8=(y-x)/y, so -1.8y=y-x, so -2.8y=-x, so y=x/2.8. Since x was old amt and y is new amt that means if the old fine particulate was 38ug/m^3, then the new fine particulate is

amount is about 14ug/m^3, which i admit doesnt match the 7ug you found, but might have been correct on a different day.Rich (talk) 08:44, 24 April 2020 (UTC)[reply]

A quick review of the main page of www.cnbc.com (in the United States) shows this article: Photos show impact of temporary air pollution drops across the world from coronavirus lockdown. In that article, they make the more precisely-stated claim:
"In Philippines’ capital city, fine particulate matter — the world’s deadliest air pollutant — dropped by 180% since quarantine measures were imposed in Metro Manila on March 16, according to the Environmental Pollution Studies Laboratory of The Institute of Environmental Science and Meteorology."
With a little bit of follow-up, we can see the Environment and Pollution Studies Laboratory (the group who originated that "180%" number) are a research group in the Institute of Environmental Science and Meteorology at the University of the Philippines Diliman, the flagship campus of the University of the Philippines System and an organization of national repute.
I am still looking for the official source (e.g. a research paper, pre-print, or press-release) for the statement that CNBC is reporting.
Nimur (talk) 19:14, 23 April 2020 (UTC)[reply]

I assume when someone decided to publish those photos, they looked for something which sounded spectacular, but as the dates and ABS-CBN story shows, this is fairly "old news". Based on the ABS-CBN story linked above by Lambian [4]), the lack of any sign of this at [5], I guessed that social media may be where this originated.

Sure enough, scrolling through the history of this Facebook page @UPIESMEPSL, I found [6]. That's actually just a comment of a Facebook post [7] by @RCMakAirtoday. So I had a look at RCMakAirtoday and found this post of theirs on the ABS-CBN story, [8] where someone questioned the 180%. In response, they pointed to this story [9] where we find:

In calculating the percentage reduction, <name removed> said she got the difference between the value recorded during the enhanced community quarantine (ECQ) and the value two weeks before it was imposed.

“Then you divide the result by the value during the ECQ and and multiply it by 100,” she explained.

(20 less 7.1 results in a difference of 12. 19, which is then divided by 7.1. The result of 1.8 is then multiplied by 100, or a reduction by 181.6 percent)

Someone else responded questioning the 180% even with this explanation but there was no further followup. I don't know if there has been more discussion in other media outlets although I had a quick search and couldn't find anything.

BTW, whole looking into this, I found the figure is mentioned in 2020 Luzon enhanced community quarantine#Environmental. So if anyone is interested in getting into a debate over WP:CALC vs figures that are published in secondary sources, they could look into whether this needs to be changed. (Although you could just exclude any percentage figure.)

Nil Einne (talk) 06:54, 24 April 2020 (UTC)[reply]

So it's exactly what I wrote below. 89.172.105.179 (talk) 17:27, 24 April 2020 (UTC)[reply]
In a formula, the Facebook explanation amounts to 100×(old amount−new amount)/(new amount). What you wrote amounted to 100×(old amount−new amount)/(baseline level), where the baseline level is the oldest of all. The Facebook explanation is precisely the theory in the post that started this thread, except for the sign. If you replay the bit of elementary algebra I posted above, but replace "180" by "−180", you end up with y = 0.357 x, a reduction of about 64%. This still does not mesh with the Facebook explanation, but by itself it makes enough sense that it wouldn't have been questioned. I'm curious what the original press release said.  --Lambiam 18:40, 24 April 2020 (UTC)[reply]
No offense meant, but as i indicated in a note underneath your algebra above, a 180% drop can be interpreted as -180%, and my algebra in that note showed that it would make some kind of sense. As the OP, I naturally want people to know I understood the mathematics.Rich (talk) 20:06, 25 April 2020 (UTC)[reply]
They could mean that it decreased to an amount where it would have to increase by 180% to regain the original level. Sadly I see non-maths people mix that stuff up all the time even when they should know better. That would be 1/2.8 = 5/14 ~ 0.357 of the original amount (or a 64.3% decrease). Or maybe they mean it dropped by 80% (to 0.2 of the original amount) and the "1" is a typo. 89.172.105.179 (talk) 01:17, 24 April 2020 (UTC)[reply]
Perhaps the 180% is measured relative to an earlier and much lower-than-current baseline level, such as that in, say, 1950 (to take a random date). If the average level has tripled since 1950, then a 180% decrease would still leave it at 120% of the 1950 level. I stress this is just a conjecture, but it seems plausible to me that such a method might be used in some scientific context, though it would be a grave and confusing error to use the figure unexplained in a report destined for public consumption. {The poster formerly known as 87.81.230.195} 2.122.178.214 (talk) 06:25, 24 April 2020 (UTC)[reply]
If scientists worth their mettle measured a level, found it to be at 120% of a certain reference value and wanted to compare this new level with an earlier level at 300% of the same reference value by calculating the arithmetic difference of the two percentages, they would report a decrease by 180 percentage points. More likely though, if that reference value was so important that it is used as the yardstick, they'd give this unit a name, say PP1950, and report a decrease from 3.0 PP1950 to 1.2 PP1950.  --Lambiam 14:43, 24 April 2020 (UTC)[reply]
A drop of 100 percent would take it to 0. What a drop of 180 percent would be is anybody's guess. ←Baseball Bugs What's up, Doc? carrots21:18, 25 April 2020 (UTC)[reply]
Under the usual definition of percentage drop, a drop of 100% would indeed bring it to zero. But under the following different definition, it would not: If percent drop in price for an item on sale meant 100*(new price-old price)/(new price), then a 100% drop would cut the price in half(which is what is normally called a 50% drop in price). Now suppose a business suit normally sells for $100.00. If the suit went on sale for $35.70, then under the new definition the price dropped by 180%, instead of 64.3%, since 100*(35.70-100)/35.70 = -180%. Note that 1.8*35.70+35.70 would bring the price back to $100.00. Rich (talk) 07:57, 26 April 2020 (UTC)[reply]
Is there any solid evidence of what CNBC actually meant, as opposed to trying to "figure it out"? ←Baseball Bugs What's up, Doc? carrots12:25, 26 April 2020 (UTC)[reply]
??? I don't see any reason to think CNBC meant anything. They just followed what was reported. The way the number was derived is discussed above based on the Philippine Daily Inquirer source linked above who communicated with the researcher who came up with the number. Nil Einne (talk) 04:31, 27 April 2020 (UTC)[reply]
Which of the links specifically explains what the 180 is about? ←Baseball Bugs What's up, Doc? carrots16:25, 27 April 2020 (UTC)[reply]

Deducing vegetation types

Hello. I am wondering if it is possible to deduce what kind of vegetation would exist in a given place that currently does not exist, for lack of habitat. I'm specifically referring to deducing what type of vegetation the Southern Hemisphere would have that would be analogous to the boreal forest/taiga and the temperate broadleaf deciduous forests of the Northern Hemisphere. If we look at a map of the world and maps of what kind vegetation types exist in different parts of the world, we can see that for the most part, all vegetation types that exist in the Northern Hemisphere have analogous types in the Southern Hemisphere as well. The specific flora may not be the same, but their adaptations, their form, their composition, will be very similar. This is true with two major exceptions, which I listed above.

So what I'm asking is, what would a Southern Hemisphere taiga and temperate deciduous forest look like? The reason that these ecosystems don't exist in the Southern Hemisphere is because of a lack of land at the right latitudes. So the north has extensive areas of taiga and deciduous forest because land exists for it in northern and eastern North America, in Russia, Siberia, Europe, and East Asia. No such land exists at the right latitudes in the south.

The reason I ask this is because I think it might be possible to deduce. The evergreen oaks of California have relatives in eastern North America that are evergreen and deciduous. The spruces, hemlocks, cedars, of the Pacific Northwest have relatives all over North America and Europe and Asia as well. So plants and trees of the same genus and families can certainly adapt to different climate types, as they have in the Northern Hemisphere. Can we make the same deduction that flora like Eucalyptus, Nothofagus, Podocarpus, can adapt to a humid continental climate and a subarctic climate like the Northern Hemisphere taiga and deciduous forests have? I know it's a stretch of the imagination, but I believe it might be possible. I just wonder if there are more educated views than mine on this topic. Thank you for your help.2600:1702:4000:5D40:C817:71F5:DF5A:F287 (talk) 19:22, 23 April 2020 (UTC)[reply]

Temperate deciduous forest exist in the Southern Hemisphere, it notes so in the lead section of that article. The closest Southern Hemisphere equivalent to taiga appears to be Magellanic subpolar forests, which aren't really taiga. As you note, there simply is no land in the Southern Hemisphere taiga belt, between the subpolar forests of Tierra del Fuego and the tundra of Antarctica is basically the Southern Ocean, where larch and spruce trees may find a wee bit hard to take hold. The closest to tiaga-like trees I can find in the southern hemisphere might be the Araucaria araucana, an alpine pine tree that grows in cold, dry areas of the Andes. --Jayron32 19:33, 23 April 2020 (UTC)[reply]
In the eucalyptus genus in Australia there is Eucalyptus pauciflora, commonly known as snow gum, thereby indicating where it grows. Rather than being at higher latitudes, it grows at higher altitudes, above 700 metres and up to a little over 2,000 metres (7,000 feet). It's known to survive temperatures down to −23 °C (−9 °F) and year-round frosts. It is, of course, evergreen, but can survive the loss of all its leaves and the death of all parts of the tree above ground (typically from fire) by re-sprouting from lignotubers. Given that there are over 700 species of eucalypt, and most seem to have evolved in quite recent geological times, the genus may well have been (and might still be) capable of creating a species to survive in even bleaker conditions, if such places existed. HiLo48 (talk) 00:07, 24 April 2020 (UTC)[reply]
The snow gum is the most common eucalypt grown in the UK, but there are about 35 others that can cope with the British weather. Not sure that they can reproduce themselves without human assistance though. Alansplodge (talk) 17:10, 27 April 2020 (UTC)[reply]

April 24

Ocean swell or something else?

A question rather than an answer from me, for a change. In the photograph of the 150 km-long Antarctic Iceberg A-38 in this BBC article, I can see an apparent wave pattern whose wavelength must be on the order of 7 km. Our article on Ocean swell states "Occasionally, swells which are longer than 700 m occur as a result of the most severe storms." So, is this pattern ordinary ocean swell, but with a wavelength some 10 times the usual maximum, or is it a different (though presumably related) phenomenon, and is there a specific name for it? {The poster formerly known as 87.81.230.195} 2.122.178.214 (talk) 05:50, 24 April 2020 (UTC)[reply]

A natural sea wave with a 7km wavelength would be travelling at just under 400 km/h. So I don't think it is that. https://en.wikipedia.org/wiki/Wind_wave Greglocock (talk) 08:12, 24 April 2020 (UTC)[reply]
Maybe internal waves? PiusImpavidus (talk) 08:21, 24 April 2020 (UTC)[reply]
You mean in an interface (thermocline) between fresher Antarctic Surface Water and saltier Circumpolar Deep Water (as shown in the diagram here)? {The poster formerly known as 87.81.230.195} 2.122.178.214 (talk) 11:06, 24 April 2020 (UTC)[reply]
This article might be relevant: [10] --Amble (talk) 15:58, 24 April 2020 (UTC)[reply]
Thanks, Amble. That article includes a description of a phenomenon on which I find we have an article, namely Infragravity wave. From the two, I gather that ocean surface waves with a wavelength of the order of 7 km can in fact occur. {The poster formerly known as 87.81.230.195} 2.122.178.214 (talk) 18:41, 24 April 2020 (UTC)[reply]

Lutheria bi-beatricis

While browsing Special:Random just now, I encountered the Lutheria bi-beatricis article. I've never seen a scientific name with a hyphen before. (It's accurate; one reference is dead and the other doesn't mention it, but the authority-control at the bottom provides confirmatory links.) Does the existence of a species under this name preclude the future use of "Lutheria bibeatricis", or could a newly discovered species be given this name? Normally I'd create the latter title as a redirect, since absence of punctuation is a good reason for a redirect, but maybe this wouldn't be a good idea if a separate species could exist under this name. Nyttend (talk) 08:33, 24 April 2020 (UTC)[reply]

The use of hyphens by those following the current Shenzhen Code of the International Code of Nomenclature for algae, fungi, and plants is described here in Article 60 and here in Article 60. (Although I don't believe it's changed for a while, see e.g. the St Louis code Article 60 and Article 23.) As for a species without a hyphen but otherwise the same name, Article 53 may come into play. Nil Einne (talk) 11:02, 24 April 2020 (UTC)[reply]
And in view of the fact that the unhyphenated variant is in fact sometimes seen for this species name,[11][12] there can be little doubt that it would be deemed to be an orthographical variant,[13] and therefore an (invalid) synonym.  --Lambiam 16:28, 24 April 2020 (UTC)[reply]
Thank you! Redirect created. I'm not surprised that there are guidelines on how names are to be formed, but I'd never seen them and didn't know where to start looking. Nyttend (talk) 12:34, 25 April 2020 (UTC)[reply]

Color of some cobalt compounds

Cobalt(III)...

  • ...chlorate: I think it unstable. But what is the color of this compound? Thanks for much.
  • ...perchlorate: I heard that it's only exists in solution. What is the color of this compound in solution? Thanks for much.
  • ...bromide: I heard that it never been prepared. Can you are the first person prepare this? Thanks for much.
  • ...iodide: also like bromide.
Cobalt(III) can oxidise water in acidic conditions. However it is quite common in complexes. eg hexammine or trisbipyridyl [14]. Do you care about complexed cobalt for your chlorate and perchlorates? Graeme Bartlett (talk) 11:38, 24 April 2020 (UTC)[reply]
See also Bromopentaamminecobalt(III) bromide Graeme Bartlett (talk) 12:11, 24 April 2020 (UTC)[reply]
Complex ions have very different colors than naked ions. Also, for the most part (with some exceptions I'm sure), the color of any ionic compound of a transition metal ion is usually predominantly due to the complex ion itself. For example, many copper (II) compounds are generally green (anhydrous) or blue (hydrated crystals). The Cu(H2O)6 ion is a brilliant deep blue color, and the hydrated crystals of things like copper (II) nitrate and copper (II) sulfate and copper (II) chloride are generally a similar blue color. That being said, the chemistry of transition metal ion complexes is messy, and depending on the exact ion complex formed, you can get vastly different colors. This thread for example contains images of two different isomers of Hexamminecobalt(III) chloride, one of which is orange, and one of which is burgundy. The moral of the story is that for MANY transition metal ionic compounds, for various reasons owing to the electron energy levels in those d-orbitals, they tend to usually be brightly colored; however predicting the color of any one of them without actually synthesizing it and looking at it is folly; likely because there is really very little energy difference across the whole visible spectrum, and tiny little differences in electron energy levels caused by whatever the particular environment around a particular transition metal ion can cause a big shift in color. Also, with regard to many of these putative compounds you are asking about, just because you can write a formula for it doesn't mean it can exist. Many of these may be so unstable that it isn't possible to observe them to any degree of reliability. --Jayron32 14:18, 24 April 2020 (UTC)[reply]
CoCl3 is already thermodynamically unstable, as can be predicted just by examining reduction potentials (Co3+ is a strong oxidant and will oxidise Cl). So CoBr3 and CoI3 seem extremely unlikely. Double sharp (talk) 06:06, 28 April 2020 (UTC)[reply]

Cobalt(IV)...

  • ...fluoride: I heard that it's unstable gas. What is the color of this compound? Thanks for much. (This is more info, it maybe help you):
  1. At -80 °C, Cs2CoF6 make a dark red solution in water.
  2. At room temperature, Cs2CoF6 have gold-colored solid.

One more time, thanks for very much. (Sorry if you don't understand, because my English is not good).--Ccv2020 (talk) 09:50, 24 April 2020 (UTC)[reply]

That fluoride CoF4 is formed at around 630K, but is only about 10−6 atmospheres in pressure. So it would not be a gas under standard conditions. The researchers studying this only observed infrared lines, and did not mention any optical spectrum or colour. The instability may be due to reaction with water breaking it up. Graeme Bartlett (talk) 11:52, 24 April 2020 (UTC)[reply]
That's a super obscure one. I was going to say that it's probably similar to [FeF4]- but that doesn't seem to really exist either. Pelirojopajaro (talk) 17:19, 24 April 2020 (UTC)[reply]

@Graeme Bartlett:Why you don't according to complex of cobalt(IV) fluoride?--Ccv2020 (talk) 01:12, 25 April 2020 (UTC)[reply]

I don't know what you mean by that, but I did fond out that Rb2CoF6 also exists. Are you asking if you can make CoF4 from Cs2CoF6? I suspect the answer is no one has done it. Graeme Bartlett (talk) 10:38, 26 April 2020 (UTC)[reply]

Construction boundary between designer and construction organisation

In construction, is there a clear boundary between what the designer is responsible for and what the contractor is responsible for or does this differ between projects? For example, would certain dimensions or materials be the responsibility of one on one project but other on another? 90.192.105.214 (talk) 17:06, 24 April 2020 (UTC)[reply]

That could depend on the local laws. ←Baseball Bugs What's up, Doc? carrots19:42, 24 April 2020 (UTC)[reply]
Normally, the plans from the designer will specify both dimensions and materials in as much detail as is relevant, which may be on account of any combination of functional, economic and esthetic factors. Thus, the contractor's freedom in these respects is very limited. It is also normal that there are negotiations between the stakeholders (in particular, including the commissioner), initiated by the contractor, whether certain substitutions or other modifications are allowed. Sometimes this may entail the need of obtaining a permit for the mods of the original plans.  --Lambiam 16:27, 25 April 2020 (UTC)[reply]

Raft foundation

Do raft foundations impose zero load on certain parts of the ground? I know it’s a way is spreading the load out over a wider area but does this mean, it could be like a bridge or will there still be some load on all areas of the ground the foundation is in contact with? 90.192.105.214 (talk) 17:59, 24 April 2020 (UTC)[reply]

Floating raft system (see article) implies that if the soil should become liquid the supported building would not sink, due to the buoyancy of its own weight of soil being displaced. In this case the load is spread over the whole area under the building. DroneB (talk) 22:33, 24 April 2020 (UTC)[reply]

Medical wording: Reduction in lethality

I was just looking at Effect of High vs Low Doses of Chloroquine Diphosphate as Adjunctive Therapy for Patients Hospitalized With Severe Acute Respiratory Syndrome Coronavirus 2 (SARS-CoV-2) Infection - A Randomized Clinical Trial, published today, and was confused by this wording:

Main Outcomes and Measures: Primary outcome was reduction in lethality by at least 50% in the high-dosage group compared with the low-dosage group.

I read "reduction in lethality by at least 50% in the high-dosage group" as meaning that the high-dosage group experienced less than half the death rate, but the paper goes on to describe the opposite, that the high-dosage group experienced more than twice the death rate (through day 13) than the low-dosage group. Yet try as I might, I can't parse the sentence to match what they clearly intend it to mean. How am I misreading this? -- ToE 19:51, 24 April 2020 (UTC)[reply]

Someone more familiar with medical research could likely explain this better but AFAICT from a quick read of the rest of the paper especially this bit:

The sample for the primary outcome (ie, reduction in lethality rate) was calculated assuming a 20% lethality incidence in critically ill patients7,23,24 and that higher dose of CQ would reduce lethality by at least 50% compared with the low-dosage group. Thus, considering a test of differences in proportions between 2 groups of the same size, 80% power and 5% α, 394 participants were needed (197 per group). Adding 10% for losses, the final sample of 440 participants was obtained. Sample calculation was performed in the R version 3.6.1 (R Project for Statistical Computing), with the functions implemented in the TrialSize and gsDesign packages.

their null hypothesis was that the higher-dosage would reduce the lethality by at least 50% compared to the low-dosage. Based on their results, the null hypothesis was rejected. Maybe see also Outcome measure. Nil Einne (talk) 21:24, 24 April 2020 (UTC)
[reply]

Someone more familiar with medical research could likely explain this better but I think you may have misunderstood the primary outcome bit. AFAICT, it isn't the outcome of their experiment. Note the part you quote comes before the results. Rather, it is the primary outcome they set before they began to prevent Data dredging or similar problems.

If they did find a 50% reduction in lethality of the high-dosage group compared to the low dosage group, their primary outcome would be affirmed and they would have statistically significant evidence for a benefit of a high dosage over a low dosage. However they did not find this and therefore they have no evidence for such a benefit. Note if you read later, it says:

The sample for the primary outcome (ie, reduction in lethality rate) was calculated assuming a 20% lethality incidence in critically ill patients7,23,24 and that higher dose of CQ would reduce lethality by at least 50% compared with the low-dosage group. Thus, considering a test of differences in proportions between 2 groups of the same size, 80% power and 5% α, 394 participants were needed (197 per group). Adding 10% for losses, the final sample of 440 participants was obtained. Sample calculation was performed in the R version 3.6.1 (R Project for Statistical Computing), with the functions implemented in the TrialSize and gsDesign packages.

Maybe see also Outcome measure and [15] and perhaps [16]. Perhaps also [17]

Nil Einne (talk) 21:49, 24 April 2020 (UTC)[reply]

I think it make sens when you replace "outcome" by "hypothesis". The were testing if higher dose would reduce the lethality by 50% and as the experiment was going the other way around, they decided to stop it early. Iluvalar (talk) 22:10, 24 April 2020 (UTC)[reply]
Thank you both. I didn't understand the term outcome in this context, and the result being the reciprocal of the hypothesis just added to my confusion. -- ToE 22:21, 24 April 2020 (UTC)[reply]
The name of this concept is statistical power: essentially, the level of improvement you're hoping to see dictates sample size. If you hope to confidently prove a very small improvement, you're going to need a bigger sample size than that needed to see if a really dramatic improvement is real or not. Sources on this I recommend are Alex Reinhart's excellent Statistics done Wrong and Blasey & Kraemer How Many Subjects? Statistical Power Analysis in Research. Blythwood (talk) 16:20, 25 April 2020 (UTC)[reply]

Deep vein thrombosis and supercentenarians question

Can someone actually recover from deep vein thrombosis while they're already a supercentenarian or at least manage to subsequently live with this condition for years in spite of them already being 110+ years old? Futurist110 (talk) 21:32, 24 April 2020 (UTC)[reply]

The annual incidence of DVT is about 80 cases per 100,000 annually. Since supercentenarians are generally in good systemic health (until they suddenly die of old age), there is no specific reason to expect a higher incidence among this group. As there are only a few hundred living supercentenarians, one should expect one case in every two or three years. There can hardly be enough cases for giving meaningful statistics. I can't think of a reason why it should be impossible for any to recover.  --Lambiam 16:14, 25 April 2020 (UTC)[reply]

"supercentenarians are generally in good systemic health (until they suddenly die of old age), there is no specific reason to expect a higher incidence among this group" - I find this statement fairly confusing especially in light of the rest of your comment. Supercentenarians may be in generally good good systemic health, but as our article says in the lead

About 5–11% of people will develop VTE in their lifetime, with VTE becoming much more common with age.[12][13] When compared to those aged 40 and below, people aged 65 and above are at an approximate 15 times higher risk.[14]

and later in the body

Acquired risk factors include the strong risk factor of older age,[5] which alters blood composition to favor clotting.[23] Previous VTE, particularly unprovoked VTE, is a strong risk factor.[24] Major surgery and trauma increase risk because of tissue factor from outside the vascular system entering the blood.[25] Minor injuries,[26] lower limb amputation,[27] hip fracture, and long bone fractures are also risks.[8] In orthopedic surgery, venous stasis can be temporarily provoked by a cessation of blood flow as part of the procedure.[21] Inactivity and immobilization contribute to venous stasis, as with orthopedic casts,[28] paralysis, sitting, long-haul travel, bed rest, hospitalization,[25] and in survivors of acute stroke.[29]

and

Some risk factors influence the location of DVT within the body. In isolated distal DVT, the profile of risk factors appears distinct from proximal DVT. Transient factors, such as surgery and immobilization, appear to dominate, whereas thrombophilias[e] and age do not seem to increase risk.[54] Common risk factors for having an upper extremity DVT include having an existing foreign body (such as a central venous catheter, a pacemaker, or a triple-lumen PICC line), cancer, and recent surgery.[11]

and

As DVT is most frequently a disease of older age that occurs in the context of nursing homes, hospitals, and active cancer,[3] DVT is associated with a 30-day mortality rate of about 6%.[1]

and especially

VTE becomes much more common with age.[12] VTE rarely occurs in children, but when it does, it predominantly affects hospitalized children.[140] Children in North America and the Netherlands have VTE rates that range from 0.07 to 0.49 out of 10,000 children annually.[140] Meanwhile, almost 1% of those aged 85 and above experience VTE each year.[3] About 60% of all VTEs occur in those 70 years of age or older,[8] and those aged 65 and above are subject to about a 15 times higher risk than those aged 40 and below.[14]

So it's well accepted and known that DVT risk increases with age. Further, while it's complicated as these things often are, and some of this increased risk may be in part due to an increase risk of underlying conditions which may increase with age, and therefore supercentenarians "good systemic health" may therefore not face quite the same risks, there is evidence that part of the reason for the increased risk is from changes associated with age that supercentenarians probably also experience. I'd also note that while supercentenarians could perhaps be more mobile than the average 85 year old (I don't really know, but to avoid needless debates I'll accept it as a possibility), I'd be surprised if they more mobile than the average 30 year old.

Therefore the assumption that supercentenarians are not at increased risk compared to the general population seems a little weird. They may not be at increased risk compared to the 1% for 85 year olds, perhaps they are even at lower risk, most likely we cannot know because of the numbers. But compared to the general population? I'm unconvinced that we have good reason to think their risk profile won't be higher.

Note that I do not disagree with the conclusion i.e. there is no reason to think supercentenarians will never survive DVT.

Nil Einne (talk) 02:39, 26 April 2020 (UTC)[reply]

I was unclear. I meant to contrast supercentenarians with "plain" centenarians, who are actually on average more often in bad health, having been kept alive to that age only thanks to modern medicinal intervention. So I may be mistaken in this, but I expect the DVT survival rate for supercentenarians to be actually higher than that for centenarians. The DVT risk factor, in the sense of the risk of incurring it, is not relevant, since the survival rate is with respect to patients already suffering from DVT.  --Lambiam 08:27, 26 April 2020 (UTC)[reply]

April 25

UV resistant germs

Per [18], "UV radiation from the sun is the primary germicide in the environment". Question: that UV radiation has been arriving for billions of years. Why haven't the germs developed resistance by now? Even if a few of them have, why not pretty much all of them? Thanks. 2602:24A:DE47:B270:DDD2:63E0:FE3B:596C (talk) 03:31, 25 April 2020 (UTC)[reply]

The best way to protect against UV is shielding. With a, say, 300μm thick shield, an organism can safely absorb a significant fraction of the UV in layer that can withstand it as the layer is dead already or can be discarded after use. The epidermis works like that. However, a 100nm virus cannot carry a 300μm shield. PiusImpavidus (talk) 11:08, 25 April 2020 (UTC)[reply]
PiusImpavidus, your phrase makes me think of "A five-ounce bird could not carry a one-pound coconut!"  :-) Nyttend (talk) 12:27, 25 April 2020 (UTC)[reply]
It's really quite staggering what an accomplishment DNA repair is given how frequently DNA gets damaged. Every day every cell in your body repairs at least 10,000 instances of DNA damage. Now bacteria and especially viruses have much shorter genomes than human cells, and obviously a lot of that isn't caused by UV, but if you're a small bacterium without much protection there will be limits to how effectively you can fix damage. And viruses have particular problems: repair requires a ton of energy, and viruses of course can't do respiration to release energy outside a cell. And RNA is less stable than DNA is. There is actually a case of viruses having a DNA repair enzyme powered by light energy, though. So fundamentally there are constraints on what they can do: it's like asking "why don't bacteria have brains": that's not the mode of living they've evolved into. Viruses have generally evolved to replicate fast and in large numbers rather than replicate good. Blythwood (talk) 11:15, 25 April 2020 (UTC)[reply]
Many RNA viruses don't even have a proofreading mechanism (e.g. influenza viruses). Coronaviruses are an exception; they have a larger-than-average genome that includes genes for proofreading.  --Lambiam 15:52, 25 April 2020 (UTC)[reply]
My comment here on the Science Desk is to do with the sloppiness of a scientific source using the word "germicide". Marketers of disinfectants and antiseptics use the word "germs" to emphasise how powerful(?) their products are. "Kills 99.9% of germs" is in a TV ad I see a lot at the moment. Unfortunately, this fails to differentiate between bacteria and viruses. Right now, this matters a lot. Looking at the source, it seems they're actually talking about viruses. I wish they'd made it clearer. I don't blame the IP. The confusion here is coming from academia! HiLo48 (talk) 11:43, 25 April 2020 (UTC)[reply]
The statement by itself is true, whether the microorganisms are bacteria or viruses (see Ultraviolet germicidal irradiation). Both the title of the article and the abstract make abundantly clear that this specific study concerns viruses; the first section of the article also compares bacteria and viruses to clarify the purpose of the study. I cannot agree that in this instance the use of the term "germicide" was sloppy.  --Lambiam 15:52, 25 April 2020 (UTC)[reply]
Using the word "germ" at all is sloppy. HiLo48 (talk) 21:01, 25 April 2020 (UTC)[reply]
So the article does not use that term at all.  --Lambiam 08:12, 26 April 2020 (UTC)[reply]
As mentioned here: "In a recent study – which looked at whether UVC could be used to disinfect PPE – the authors found that, while it is possible to kill the virus this way, in one experiment it needed the highest exposure out of hundreds of viruses that have been looked at so far. The amount of ultraviolet required varied widely, depending on factors such as the shape and type of material the virus was on....... “UVC is really nasty stuff – you shouldn't be exposed to it,” says Arnold. “It can take hours to get sunburn from UVB, but with UVC it takes seconds. If your eyes are exposed… you know that gritty feeling you get if you look at the sun? It’s like that times 10, just after a few seconds.”" Count Iblis (talk) 19:39, 25 April 2020 (UTC)[reply]
Because there's no significant selection pressure to drive the development of such a trait. Any trait has a cost, taking resources that could be invested in something else. Let's look at the history of life on Earth. There was little life on land for about half of Earth's history, because there was no oxygen in the atmosphere and thus no ozone layer to block high-energy UV from the Sun. Essentially all life was in the ocean. (All life was microscopic as well.) The Great Oxidation Event produced an oxygen atmosphere, which was essential to the development of large organisms. Some organisms have some kind of UV resistance, such as in endospores that some bacteria produce to survive harsh environments. But that gives a good illustration of why such traits are not everywhere. Endospores are "vegetative". They don't move around or "do" anything; the bacteria basically erects a fortress and goes into "hibernation" to try to survive until the environment is more hospitable. Or another good example: human skin color. Humans developed dark skin when our ancestors lost fur, to shield against UV. Then some human populations migrated to higher latitudes and went back to having light skin, since this was not as necessary in environments with less sunlight. In this case there was also selection pressure driving the switch back to the light skin phenotype, as UV is needed for vitamin D production. --47.146.63.87 (talk) 22:17, 25 April 2020 (UTC)[reply]
I disagree with this–as I said above, clearly it's beneficial to at least some viruses to have DNA repair enzymes, as they package enzymes with them inside the virus particle. And bacteria have tons of DNA damage pathways. Blythwood (talk) 01:29, 26 April 2020 (UTC)[reply]
Uh, I don't see how we're in disagreement. Some level of DNA repair is necessary in basically all organisms because otherwise their DNA would turn to mush from just random unwanted chemical reactions, if nothing else. I was just describing why more microbes don't have the ability to withstand prolonged exposure to high amounts of UV. Some do, like radiotrophic fungi. But it's just not that beneficial in most microbial niches. --47.146.63.87 (talk) 01:57, 26 April 2020 (UTC)[reply]
some bacteria have resistance, for example Deinococcus radiodurans about 1000 times as resistant to radiatin than humans. Graeme Bartlett (talk) 10:32, 26 April 2020 (UTC)[reply]
To actually answer the question, deductions from the article tells you. The most effective UV to inactivate viruses is 260 nm. But the UV at Earth's surface is above 290 nm. Also, I do know from past research, that the vast majority of viruses in the world, are in ocean's. 67.175.224.138 (talk) 04:17, 28 April 2020 (UTC).[reply]

The Great pyramid of Giza: a question to Egyptologists

still pseudoscientific nonsense
The following discussion has been closed. Please do not modify it.

THE GREAT PYRAMID AND THE DIMENSIONS OF THE EARTH Much has been written on the mysteries of the Great pyramid and writers like Graham Hancock have used them to support the idea that a technologically advanced civilization was present on Earth more than 10.000 years ago and, before being wiped out by a cometary impact, left traces of its advanced knowledge, like the Precession of the equinoxes, as a message to successive civilizations, from Egypt to South-America (an alternative is that visiting aliens provided such information). The speculations by Hancock and company did not stand critical scrutiny and have all been shown to be without any foundation. All but one: a relationship between the dimensions of the Great pyramid of Giza and the dimensions of the Earth. This is discussed in one of Hancock’s books (Magicians of the Gods, 2016), where the fact that multiplying perimeter and height of the pyramid by the number 43.200 gives-with an excellent approximation- the dimensions of the Earth’s equatorial circumference and polar radius respectively, is taken as one example of ancient knowledge left for future generations. The Egyptians had no knowledge of the Earth’s dimensions and Precession of the equinoxes (the “magic” number 43.200 is, according to Hancock, related to the phenomenon of Precession of the Earth’s axis), therefore only a civilization with such knowledge could have encoded these data in the pyramid, hence there must have been a very advanced civilization long before the Egyptians. Very advanced indeed: understanding the Precession of the Earth’s axis requires modern astronomy. The pyramid/Earth relation, originally proposed by John Taylor, an engineer with Napoleon’s expedition in Egypt and later by the Astronomer Royal of Scotland Charles Piazzi-Smith in 1864, was based on a suggestion by the astronomer John Greaves in 1706 about the “pyramid inch”, a unit of measure used by the builders of the Great Pyramid, a fact later dismissed by the Egyptologist Flinders Petrie in 1883. We can therefore forget the pyramid inch and the Taylor-Smith theory, and the number 43.200 has of course nothing to do with Precession, all the numbers supposedly related to an ancient knowledge of Precession have been shown to be pure fantasies (see e.g. “Pick a Card, Any Card - How Hancock Finds Precessional Numbers” by John Wall 2005, The Hall of Ma’at on the Internet).

And yet such relation exists, as anyone can find out with simple math using the metric system. The dimensions of the original pyramid (according to Egyptologists) are: perimeter=921.44m, height=146.60m. Multiply by 43.200 and find 39806.208Km and 6333.12Km respectively. Modern measurements give the Earth’s equatorial circumference as 40035.41Km and the polar radius as 6356.988Km. An incredible “coincidence”! The probability that given a man-made structure, any structure, a number can be found such that, if multiplied by the dimensions of the structure, it will reproduce the dimensions of any celestial object, is exceedingly small and the case of the Great pyramid can therefore hardly be attributed to a coincidence. And certainly it cannot be attributed, following Hancock, to the existence of an ancient advanced civilization, the evidence against such hypothesis is overwhelming. A visit by aliens providing mankind with information about Precession and Earth dimensions is a possibility but it has an exceedingly small probability of being true. As I argued in my book “Il mondo dell’improbabile Homo sapiens”(The world of the improbable Homo Sapiens), the probability that there is life elsewhere in the Universe is so close to 1 that we can take it as a certainty, but the probability that a life-form developed somewhere beyond the stage of single-celled organisms is so small that we can take it as null. And single-celled organisms do not study Precession and do not travel to other planets. Sherlock Holmes said: ”When you rule out the impossible, what is left, however improbable, must be the truth”. But what is left? Do Egyptologists have any suggestions for this incredible case? 151.73.116.99 (talk) 16:37, 25 April 2020 (UTC)[reply]

Your numbers are written in a way that is confusing. Is 43.200 in fact 43,200? There was no advanced civilization before Egyptians, there was no aliens. The earth radius was measured by Eratosthenes[19] in 3rd century before CE. No computer was needed AboutFace 22 (talk) 17:43, 25 April 2020 (UTC)[reply]
Note: many countries write one thousand as 1.000 and not 1,000 --OuroborosCobra (talk) 18:19, 25 April 2020 (UTC)[reply]
Yes, but then he should have written 39806.208Km as 39806,208Km AboutFace 22 (talk) 19:22, 25 April 2020 (UTC)[reply]
Not really. While the OP's comments have been nonsense, I don't think it makes sense to make a big deal over a mistake. I think most people with sufficient level of English to be able write a coherent (even if nonsense) paragraph are also aware of the norms for delimiters, and decimal separators for most English speakers and therefore generally use the decimal point as the decimal separator when communicating with generic English speakers to avoid confusion. However if what you're use to the the comma, it's likely fairly easy to make a mistake on occasion. Nil Einne (talk) 18:16, 26 April 2020 (UTC)[reply]
I should clarify that I'm not saying there's anything wrong with seeking clarification or providing guidance if there is uncertainty. I simply mean we should treat it as some major mystery or something that makes no sense, when even before the OP's comment below, it seemed likely based on familiarity with the differing conventions that it was simply a mistake most likely arising from trying to write in a convention you're not used to. Nil Einne (talk) 02:14, 28 April 2020 (UTC)[reply]

Reply to comments: first comment:True I should have used a coma rather than a dot,but-as stated in the second comment- many countries,including mine,use the dot.Anyway the meaning of numbers should be obvious,everybody knows that the Earth radius is of order 6000Km,coma or dot! Of course there was no advanced civilization and no aliens, this is exactly what is said in my talk!We all know that Eratosthenes measured the Earth's radius but it is irrelevant to my argument, the pyramid was built thousands of years before! The comments are totally irrelevant to my question and so is the general heading "pseudoscientific nonsense".My talk has nothing to do with pyramidology or pseudoscience,all the nonsense by Hancock,Taylor or Piazzi-Smith is clearly criticized and set aside leaving only a "fact":the relation between the dimensions of the pyramid and the Earth's,this can be checked by anyone, it is a mathematical fact with no relation to any pseudoscientific nonsense. I only asked if Egyptologists have any answer for this "fact": where is the pseudoscientific nonsense?151.73.116.99 (talk) 14:41, 26 April 2020 (UTC)[reply]

If you divide something by something you get a number. Here some of the numbers are 43502 (perimeter_p/perimeter_Earth) and 43362 (side_p/r_polar), which are I suppose somewhat close to 43200 if that number meant something. The precession of the Earth number would be the axial tilt, which is quasiperiodic with the period being somewhere around 41,000 years, but motion is irregular and not quite periodic. Judging from WP knowledge, the average period lately has been ~41,040 years. You'd think that if the mystic pyramid builders could measure Earth size and axial tilt period so closely, they would know better than to get it wrong by 6%. And I say that all while shutting an eye to the sheer quantity of ratios, lengths, distances etc. out there, not to mention random pretty numbers like 43200 = 33402. You can get it a lot closer than 6% by choosing the right measurement (and probably a different pyramid inch). Think of the Ley lines, uncanny arrangements between prehistoric sites in Britain. You'd never expect to be able to fit so many of relatively few objects on a straight line (give or take a few miles to the side) by pure chance, right? Wrong. 93.136.55.42 (talk) 15:41, 26 April 2020 (UTC)[reply]
Your formulation is just another way leading to my question.Is it not strange (very strange) that the ratios of the exact dimensions give very similar numbers? Identical within some approximation and both close to 43200,a number with no particular meaning, certainly not related to the precession of equinoxes. If you repeat your calculation with any other celestial object get very different numbers (for the Moon,for instance, the ratios are 23703 and 11890, quite different!).Only for the Earth these numbers are "almost" identical. I find it very strange and, although I believe that,improbable as it may be, it must be a coincidence with no hidden meaning, I wandered if Egyptologists have any explanation for this. Again:where is the pseudoscientific nonsense? 151.73.116.99 (talk) 20:16, 26 April 2020 (UTC)[reply]
Since the circumference of our planet divided by its radius is close to 2π (within a fraction of 1%), the whole thing amounts to the observation that the ratio height : base-length of the Great Pyramid of Giza, which equals 146.7m/230.34m = 0.6369 (using the data from our article), is approximately equal to 2/π = 0.6366. No need to get any astronomy involved. My money is on this being a coincidence, but should the architect, for whatever reason, have chosen to use the ratio circle-diameter : half-circle-circumference for the pyramid, they surely could have done that to this precision with the means available to them.  --Lambiam 04:59, 27 April 2020 (UTC)[reply]
At last a clear answer to my question. Thank you.Elementary!(and of course my calculation for the moon was wrong, used wrong data) 151.73.116.99 (talk) 16:09, 27 April 2020 (UTC)[reply]
The angle of the Great Pyramid is based on centuries of experimentation by Egyptian architects in determining the angle of repose for such a structure. Calculations involving angles (i.e. trigonometry) frequently have π pop into them somewhere, so it is unremarkable that a well-constructed pyramid at it's ideal angle of repose would end up with π coming out of the ratios somewhere; it doesn't actually require knowledge of π to produce it in a calculation. It pops out of lots of things like this all the time. It just comes from the geometry, and will arise naturally in the ratios of such constructions. I can't be bothered to work out the math, but I've seen enough similar calculations to be entirely unsurprised that the ratio of the base of a well-constructed pyramid to its height would have a factor of π somewhere. --Jayron32 13:12, 27 April 2020 (UTC)[reply]
The Angle of repose of a granular material depends on its (NOT "it's") density, the surface area and shapes of the particles, and the coefficient of friction of the material. Unless he has access to a reliable formula for calculating the repose angle that Wikipedia lacks, it should surprise an intelligent person if a correct value of π (see link) were found here. DroneB (talk) 15:39, 27 April 2020 (UTC)[reply]

April 26

dish soap as solvent

I overcooked something at dinnertime so there is dried stuff stuck to the bottom of the pot. No big deal, soak it overnight then wash in the morning. Question: would squirting in some dish soap help the stuff dissolve faster? I do that sometimes but it's hard to tell by experiment, without a lot of repeated trials and a controlled amount of overcooking, soak time, etc. All of that defeats the simplicity of the basic plan of not having to pay attention to it while it soaks. Thanks. 2602:24A:DE47:B270:DDD2:63E0:FE3B:596C (talk) 07:34, 26 April 2020 (UTC)[reply]

In the interest of scientific progress you should overcome your aversity to careful experimentation. Now that so many more people have, overnight, become amateur cooks, this will be a great service to humankind. As dish soap serves as a powerful surfactant, I expect it will help to soak and dissolve the starch that serves as a glue, which otherwise might be shielded from the water by a coat of lipids. Using warm water also contributes by liquefying fats and making oils less viscous. For overnight soaking it may make little difference, though. If the bottom stuff is severely burnt and your pot is not made of aluminium, an additional table spoon of baking soda will do wonders.  --Lambiam 08:00, 26 April 2020 (UTC)[reply]
In my experience Bio washing powder makes dissolving baked on overcooked food much easier. Soak overnight. YMMV--Phil Holmes (talk) 08:58, 26 April 2020 (UTC)[reply]
Another proved technique is allow a dishwasher tablet to dissolve in the offending pot. Scope for a comparative study perhaps? Alansplodge (talk) 12:13, 26 April 2020 (UTC)[reply]
Just a clarification on terminology: In dish soap, the actual soap stuff (likely something like sodium lauryl sulfate or a similar compound) is a surfactant and detergent and not a solvent itself. The compound by itself is a waxy solid and not particularly good at dissolving anything. What soaps do is they make water a better solvent. The water is still the solvent, the soap just improves water's ability to dissolve things by both breaking up the surface tension of the water (the surfactant action) and by being amphiphilic, which basically means it has an end that 1/2 of it can dissolve in the dirt, and the other half can dissolve in the water, allowing the water to dissolve dirt it otherwise wouldn't very well (the detergent action). The water itself softens the grime; what the soap does is make it easier for the water to do its job. When I soak dishes, I always add a little soap to the water to speed things along. Periodic scrubbing and rinsing is good as well, as you sometimes need to remove the softened layer of gunk to expose more of the gunk to the soapy water. --Jayron32 13:02, 27 April 2020 (UTC)[reply]

Strains and sequences

Are strains and sequences two different things? I speak in respect of Severe acute respiratory syndrome coronavirus 2. I have heard there are over 6,000 sequences. Is this to do with how DNA reacts to the virus? I assume there are only a handful of known strains? I would appreciate it if someone could help clear this up for me :) Uhooep (talk) 12:21, 26 April 2020 (UTC)[reply]

It is quite possible that 6,000 samples of SARS-CoV-2 have been sequenced. They may be identical to each other or different. But "strain" only refers to a viral population sufficiently different from other viruses of the same species. Ruslik_Zero 13:37, 26 April 2020 (UTC)[reply]
The company deCODE genetics in Iceland is testing large numbers of people, initially only of high-risk cases but later by random sampling (currently 6% of the population), and is sequencing the SARS-CoV-2 genome of every positive test. As of April 14, 2020, they had sequenced SARS-CoV-2 from 643 samples.[20] They find a high mutation rate which effectively allows them to reconstruct who infected whom. Clustering the collection of genomes into a small number of strains will always have something arbitrary: the choice of when to stop.  --Lambiam 04:12, 27 April 2020 (UTC)[reply]

Ringdown and no-hair theorem

"Immediately following the merger, the now single black hole will “ring”. This ringing is damped in the next stage, called the ringdown, by the emission of gravitational waves. The distortions from the spherical shape rapidly reduce until the final stable sphere is present, with a possible slight distortion due to remaining spin." - says our Wikipedia page.

What exactly is this ringdown? Is it a bad choice of words, so that the ringdown is just an echo, like the wobble in the membrane of a drum after the drum is stuck, or do post-merger deformations of (inside??) the black hole produce the waves? If the second, how does it square with the no-hair theorem (which says the black hole is completely described by about a dozen scalars) even if no overtones? 93.136.55.42 (talk) 15:54, 26 April 2020 (UTC)[reply]

This will be investigated by the proposed TianQin (Chinese: 天琴计划) space-borne gravitational-wave observatory consisting of three spacecrafts in Earth orbit. See Constraining modified gravity with ringdown signals: an explicit example, Phys. Rev. D volume=100 issue=8 at=084024, 14 October 2019. DroneB (talk) 17:47, 26 April 2020 (UTC)[reply]
Binary black hole § Ringdown: The article you were reading. Also no-hair theorem. From that article, the no-hair theorem is only conjectured for "stable" black holes. "Unstable" ones, like one immediately after a merger, may have more degrees of freedom. I'm afraid I'm not an expert on general relativity so I'm not sure what is involved in modelling these. Since it's difficult to observe mergers in detail most of this is based on mathematical models. And of course we can't observe anything beyond the event horizon. --47.146.63.87 (talk) 22:41, 26 April 2020 (UTC)[reply]
I would have written the content in the article you(s) have been reading. In the modelling section it becomes clear that what the ringdown is, is some sort of scattering of the gravitational waves from the late inspiral. Either similar to a simple echo, or an echo that has been twisted around by frame dragging by a spinning black hole. Because of the infinite redshift at the event horizon, you are never really going to observe a no-hair simple infinite age blackhole. Instead you are going to see a highly slowed down version of the close to final merger. The modelling can calculate what observers in different reference frames will "experience", but we are interested in the observer at infinity. I think the descriptions of echo are closer to the mark, than a vibrating ellipsoid. Graeme Bartlett (talk) 23:55, 26 April 2020 (UTC)[reply]
I asked an astro professor about something that a long time ago: if you had heavy objects (e.g. a binary star system) moving around inside the event horizon, could you detect that from the outside? He seemed to think yes. 2602:24A:DE47:B270:DDD2:63E0:FE3B:596C (talk) 00:09, 27 April 2020 (UTC)[reply]
well that would be a form of ring down, but you would never see the binary star pass the even horizon. Graeme Bartlett (talk) 12:43, 27 April 2020 (UTC)[reply]
That's pretty much why I'm asking this question, if the ringdown is the "echo" of pre-merger events that's fine, but if it's the echo of post-merger movements inside the event horizon, wouldn't that tell us something about the arrangement of matter inside the horizon? And wouldn't that then tell us something about the arrangement of matter before the merger and/or be some kind of a causality violation? 93.136.46.218 (talk) 15:08, 27 April 2020 (UTC)[reply]
Do the shapes bounded by each event horizon remain the same during the merging process? Or do they merge to form one joint event horizon that takes some time to settle down into a rotation-symmetric shape? And if so, might the latter process involve some form of oscillating? (The traditional concept of shape is ill-defined here, but the concept of rotational symmetry applies without difficulties.)  --Lambiam 19:13, 28 April 2020 (UTC)[reply]

April 27

Is all hypochlorite salts of transition metals are colorless?

I'm don't sure that all hypochlorite salts of transition metals (like Fe(ClO)3, Cu(ClO)2, Rh(ClO)3, Pt(ClO)4,...) will colorless. So what do you think for the color of them? Thanks for much (Sorry if you don't understand, because my English is not good).--Ccv2020 (talk) 07:02, 27 April 2020 (UTC)[reply]

Might be difficult to make some of those. Adding Fe3+ to NaClO solution creates a giant cloud of chlorine gas, as seen in multiple industrial accidents such as [21]. DMacks (talk) 07:19, 27 April 2020 (UTC)[reply]
As noted above, I can't find any evidence the above compounds exist at all. Any reaction that would putatively create them is likely outcompeted by some kind of redox reaction that would reduce the ClO- to Cl2. I can't find an MSDS on any of them, which again, is a good sign that they don't exist. I'll repeat what I said last time: just because you can write a correct formula for a compound doesn't mean it can actually exist. Describing the color of a non-existent compound is a futile thing. --Jayron32 12:53, 27 April 2020 (UTC)[reply]
For attempts at making copper hypochlorite, a precipitate of cupric hydroxide / copper oxychloride forms. Quite a few of the oxychloride compounds are coloured eg TiOCl VOCl VOCl2 VOCl3 and FeOCl. These oxychlorides do not contain O-Cl groups though. Graeme Bartlett (talk) 23:12, 27 April 2020 (UTC)[reply]
Yes, just to clarify that, those are compounds that contain oxygen atoms and chlorine atoms as separate moeities, not as hypochlorite ions. That's a very different animal.--Jayron32 13:29, 28 April 2020 (UTC)[reply]

Address of a medical machine

Hello, I would like the address of the machine, which is in the USA, which can maintain in life the head despite the body is ceasing to function , please ? Thank you in advance. — Preceding unsigned comment added by 93.23.124.43 (talk) 15:48, 27 April 2020 (UTC)[reply]

Are you asking about Advanced Life Support, about Cryonics, or about something else entirely? -- ToE 16:26, 27 April 2020 (UTC)[reply]
Outside of Futurama, I don't think such a machine exists. Even cryogenically frozen heads are still dead. --OuroborosCobra (talk) 16:34, 27 April 2020 (UTC)[reply]
The OP might be talking about Alcor, which is where the remains of Ted Williams are on ice. ←Baseball Bugs What's up, Doc? carrots17:50, 27 April 2020 (UTC)[reply]

Hi, just wanted to ask questions concerning the subject above - What will be the impact of the asteroid on the earth? - Where it will hit hard?

Please explain it in less 'Scientific terms', my field is quite different

I'd be grateful Thanks --RazorTheDJ (talk) 18:09, 27 April 2020 (UTC)[reply]

Wikipedia has an article titled (52768) 1998 OR2 that should answer your questions. The most relevant sentence I can quote to answer your question by reading that article is "On 16 April 2079, this asteroid will make a near-Earth encounter at a safe distance of 0.0118 AU (4.59 LD), and pass the Moon at 0.0092 AU (3.6 LD)" Which is to say the next closest approach to the earth by this asteroid will be a distance of 4.59 times the distance the moon is from the Earth. In your lifetime, there is zero chance of it having any impact. --Jayron32 18:18, 27 April 2020 (UTC)[reply]
Hi @Jayron32, thank you for your response
What's all about the April 29th 2020 frenzy of the asteroid 'crushing' the earth? Please explain
P.S I'll probably be alive in 2079 at a proud age of 76!!😁--RazorTheDJ (talk) 19:52, 27 April 2020 (UTC)[reply]
It is also making a "close" approach on April 29th. It is not "crushing" the Earth. It will miss us, at its closest it will be 16 times further away from the Earth than the Moon, and we don't generally consider the Moon to be crushing us. It will not hit us. We know its closest approach to an accuracy of +/- 7km, which is incredibly accurate. --OuroborosCobra (talk) 19:55, 27 April 2020 (UTC)[reply]
Where can I see this "April 29th 2020 frenzy"? HiLo48 (talk) 03:17, 28 April 2020 (UTC)[reply]
See Snopes.  --Lambiam 04:50, 28 April 2020 (UTC)[reply]
There are lots of rocks that get much closer to the Earth than this one. See e.g. spaceweather.com table of Near Earth Asteroids. Dark red entries indicate rocks that come closer than the Earth-Moon distance, lighter red lines are less than five lunar distances. All of that happens several times every month. NASA has a Near Earth Object database where you can dig for more orbital elements of rocks. 85.76.44.116 (talk) 06:51, 28 April 2020 (UTC)[reply]
Thanks so much for your responses,all of you. At least there's nothing gonna annihilate us, for now. So what's all the fuss of it being 'potentially dangerous to earth' ? Why should some websites spread fear if at all it will miss us?--RazorTheDJ (talk) 12:13, 28 April 2020 (UTC)[reply]
Maybe because they are sensationalist and have some way of benefiting from the attention. That's existed for a long time, in the form of "buy my doomsday pamphlet" or "visit my website as clicks get me revenue," etc. That, or people who genuinely do not understand the science and spread hysteria. That also has existed for a long, long time. --OuroborosCobra (talk) 14:47, 28 April 2020 (UTC)[reply]
Will it be seen by the naked eyes or with the aid of a telescope as it passes?--RazorTheDJ (talk) 16:51, 28 April 2020 (UTC)[reply]
If I did my maths right, the rock will have an angular size of 0.0002 degrees. Which is like looking at a car tail light at a distance of 200 kilometers. So pretty much negatory on the naked eye. Telescope - sure, though probably you'll want to set a longish exposure time on your telescope camera. 85.76.44.116 (talk) 17:03, 28 April 2020 (UTC)[reply]

April 28

Some bird

What's this bird? Yellow beak and yellowish (yellow-greenish) patches on the upper side, spotted in Warsaw, Poland. Thanks. Brandmeistertalk 08:57, 28 April 2020 (UTC)[reply]

Common starling. Mikenorton (talk) 09:02, 28 April 2020 (UTC)[reply]

Duplicate Wikidata items?

I came across two Wikidata items, Q23015579 and Q132641 which are both called "Glyptodontidae" where one has the description "subfamily of mammals (fossil)" but the other has the description "family of mammals." However, otherwise they appear to be about the same thing. Are these items duplicates? DraconicDark (talk) 15:42, 28 April 2020 (UTC)[reply]

There's a fairly consistent latin naming system for various Taxonomic ranks, with consistent use of suffixes for specific ranks. In this case, the -idae suffix is for a zoological family, and the -inae suffix is for zoological subfamily. Other than that, I don't know how to solve any knock-on problems from the double naming, but the -idae suffix indicates that that specific word is for a family and not a subfamily. --Jayron32 15:48, 28 April 2020 (UTC)[reply]
@Jayron32: Upon further inspection, it turns out Q132641 is called "Glyptodontinae" which would fit the naming convention you stated. However, there still appears to be significant overlap between the subjects, and apparently the glyptodonts' classification isn't as clear as I had originally thought. This makes the question of whether to merge the items more complicated. DraconicDark (talk) 16:10, 28 April 2020 (UTC)[reply]
Taxonomic classifications change alarmingly frequently, and the subfamily Glyptodontinae is currently classified under the family Chlamyphoridae, but that doesn't mean there didn't used to be a family named "Glyptodontidae". Whether that family was subsumed into Chlamyphoridae and reclassified as a subfamily, or whether Chlamyphoridae was formerly called Glyptodontidae and just renamed, I couldn't say, both are possible and there are numerous examples of each happening, as well as other permutations (Glyptodontidae containing several subfamilies, including Glyptodontinae as well as several others, and then it was just deleted and its subfamilies added to Chlamyphoridae for example). You'd need an actual taxonomist to be able to make a decision here; I'm just a well-read chemist myself and don't have a lot of training here beyond what I find in Wikipedia articles. --Jayron32 16:15, 28 April 2020 (UTC)[reply]
Explained at Glyptodon. Jayron32's suggestion of a former family subsumed into another is correct.--Khajidha (talk) 17:37, 28 April 2020 (UTC)[reply]
@Khajidha: So should the Wikidata items be merged? DraconicDark (talk) 18:25, 28 April 2020 (UTC)[reply]
Not being clear as to what Wikidata is or what it does or how it's used, I do not have any opinion on this. --Khajidha (talk) 21:08, 28 April 2020 (UTC)[reply]

Higher/lower voltages with respect to fire safety

In the United States, the standard voltage used is 110V. In many other countries, the voltage is much higher. Is there any consensus in the engineering community as to which one is safer? I would think higher voltages are safer since circuits with a higher voltage do not require as high of a current as lower voltage circuits, but obviously electrical engineering is a bit more complex than that, so I might be wrong. --PuzzledvegetableIs it teatime already? 17:42, 28 April 2020 (UTC)[reply]

Aren't both of you wrong? The standard in the U.S. is 117 rms. 67.175.224.138 (talk) 22:11, 28 April 2020 (UTC).[reply]
I cited a reference, but it's only Wikipedia. What's yours? --76.71.6.31 (talk) 22:21, 28 April 2020 (UTC)[reply]
Either one can kill you. What kills you is the electric current going through your body; see our article on Electrocution. The higher the current, the sooner it is fatal. The strength of the current is determined by Ohm's Law and is a function of voltage and resistance. Given the resistance of your body, if it is not isolated from ground, the current is directly proportional to the voltage. So at 220V the current will be twice that at 110V, and will be deadly sooner.  --Lambiam 18:48, 28 April 2020 (UTC)[reply]
Actually at 220 V you need twice less current to draw the same power, so the fuses typically have less amps. 93.136.9.236 (talk) 23:33, 28 April 2020 (UTC)[reply]
What you need is less, but that doesn't have to do with how the current manifests. Current is determined by Ohm's Law, and your resistance does not differ because you are standing in Europe and not the US. If your body resistance isn't changing, then the current resulting from 220 V traveling through you will be double. --OuroborosCobra (talk) 23:40, 28 April 2020 (UTC)[reply]
Do fuses have different resistances in Europe? 67.175.224.138 (talk) 23:44, 28 April 2020 (UTC).[reply]
For fire safety, the issue is the heat generated; see Joule heating. The heat is proportional to the product of current and voltage. So a voltage that is twice as high but a current that is only half as high produce the same amount of heat in the wiring. The amount of useful work is also proportional to that product; see AC power. So in the end the fire hazard, given the same amount of work, should be equal.  --Lambiam 19:02, 28 April 2020 (UTC)[reply]
The rate of heat generation in a resistance is indeed given by the product of the current through it and the voltage between its ends. But the voltage drop across a poor connection in domestic wiring is not equal to the supply voltage, since the connection is in series with some domestic appliance such as an oven or kettle.
Unless the connection is very bad indeed, its resistance will be far lower than that of the appliance. In that case the current in the circuit is approximately the power rating of the appliance divided by the supply voltage (so double the current for half the supply voltage). The voltage dropped by the poor connection is the current times its resistance (so doubled by doubling the current). That means for an appliance of given power, and a connection of given resistance, the heating at the connection is quadrupled by halving the supply voltage, consequently increasing the fire risk.
This is an over-estimate, as we have neglected the fact that the poor connection will reduce the current slightly (though it is easy to correct for that). catslash (talk) 00:50, 29 April 2020 (UTC)[reply]
My current [pun not intended] calculations suggest even a factor of 16, assuming that the resistance of the poor connection is small compared to that of the appliances hooked up. The reason is that (to achieve the same amount of useful work or heating) the appliance resistance increases proportionally to the square of the voltage. The relative contribution of the poor connection to the voltage drop over the serial circuit of poor connection plus appliances then decreases proportionally to the inverse of that square, giving another factor of four.  --Lambiam 05:26, 29 April 2020 (UTC)[reply]
I'm not following you. If the source voltage doubles and the load impedance is quadrupled to maintain the same power, then the ratio of load_impedance : I^2R_loss_of_poor_connection does indeed increase by 16X, but isn't that a meaningless ratio to even consider? -- ToE 13:13, 29 April 2020 (UTC)[reply]
I have now redone the algebraic calculations using a computer algebra system. I must have made some error in the calculations done by hand. To a first approximation, the heat generated in a bad (high-resistance) wire is indeed inversely proportional to the square of the source voltage, when in a serial circuit with an appliance of a given power consumption.  --Lambiam 12:17, 30 April 2020 (UTC)[reply]
@Lambiam: You have written "... produce the same amount of heat in the wiring." When you use the word "wiring" I will assume you mean the two conductors that join the power source to the appliance; in which case the amount of heat produced in the wiring is not the same regardless of the voltage at the source. As you know, the heat produced in a conductor is the square of the current multiplied by the resistance of the conductor. If an appliance draws a given power P, and we consider first one supply voltage, and then consider doubling that supply voltage but still supplying power P to the appliance; doubling the voltage will cause the current in the wiring to halve. The heat produced with half the current will be only one-quarter of the heat produced in the first case, simply because joule heating is directly proportional to the square of the current providing the resistance is unchanged. So the risk of fire caused by joule heating in the wiring decreases dramatically as supply voltage is increased to an appliance drawing a given power P. Dolphin (t) 15:20, 29 April 2020 (UTC)[reply]
By "wiring" I was thinking of the wires in the walls, which in older buildings are often not in good shape, and by "voltage that is twice as high" I meant the voltage drop across the wiring. However, the latter is not simply proportional to the voltage supplied by the supplier.  --Lambiam 12:17, 30 April 2020 (UTC)[reply]
Australian switched dual 3-pin socket-outlet. See AS/NZS 3112#Switch requirements. -- ToE 17:03, 29 April 2020 (UTC)[reply]
Here in Australia, with 240 volts, power points/wall sockets almost always have switches, meaning that devices can remain plugged in but not be electrically alive. My limited observation is that switches don't generally exist on US wall sockets with 110 volts. While not a direct consequence of the different voltages, perhaps the switches are there because of the higher voltage involved, and definitely make things safer. HiLo48 (talk) 02:39, 29 April 2020 (UTC)[reply]
A frequent feature in American homes is that some of the wall outlets will be controlled by a switch, though not necessarily a direct part of the outlet. The purpose of that setup is to allow floor lamps and such to be turned off by the switch. Outlets that are near water sources, such as sinks, may have a different type of switch, kind of a "breaker" which trips if there's a short. ←Baseball Bugs What's up, Doc? carrots03:07, 29 April 2020 (UTC)[reply]
I always called them GFIs but wiki calls them RCDs. hmm. Pelirojopajaro (talk) 13:54, 29 April 2020 (UTC)[reply]

April 29

Planets

In the Planet article, it says that in order to be considered a planet, an astronomical body needs to be massive enough to be rounded by its own gravity. About how much mass is required for this? Is there some kind of "minimum mass" for a planet? 193.210.228.37 (talk) 11:43, 29 April 2020 (UTC)[reply]

This will depend on how strong the material is. If it is the very weak solid nitrogen, the smallest size would be much smaller than for an iron nickel asteroid. Graeme Bartlett (talk) 11:45, 29 April 2020 (UTC)[reply]
Here is an assessment in terms of radius. The radius is more useful for astronomers because it's easier to measure than mass (you need e.g. a satellite to measure mass). As expected the necessary radius depends a lot on the body's composition. 93.136.9.236 (talk) 15:30, 29 April 2020 (UTC)[reply]
Pluto is certainly round, but Tyson decided it wasn't a planet anymore, so it isn't. ←Baseball Bugs What's up, Doc? carrots21:49, 29 April 2020 (UTC)[reply]
Because being round isn't the only qualifying factor to make something a planet. Tyson didn't decide anything, either. The International Astronomical Union decided on a definition. Tyson has been a proponent of said definition, but it wasn't his call. --OuroborosCobra (talk) 22:49, 29 April 2020 (UTC)[reply]
He championed it, so he gets the blame. ←Baseball Bugs What's up, Doc? carrots03:57, 30 April 2020 (UTC)[reply]

What exactly does it mean for a photon to have an amplitude?

Given the extent to which photons cannot be described as classical waves, what exactly does it entail to measure the amplitude of one? As in, what are you physically measuring and called the 'amplitude', if the photon itself does not truly possess a 'height' the way a classical wave might. Apologies for any misconceptions inherent to the question itself. — Preceding unsigned comment added by Opossum421 (talkcontribs) 11:50, 29 April 2020 (UTC)[reply]

Amplitude in quantum mechanics refers to the level of probability of making that measurement at that value. See Probability amplitude (though that article like many at Wikipedia is probably too technical for someone unfamiliar with the field. Le sigh.) The basic way to think of the wave function is that it isn't a wave in space-space, it's a wave in probability space. Only the position wave function includes space-space in it, and even that isn't telling you where the particle is, it is telling you where the particle is likely to be if you were to try to interact with it. The particle isn't anywhere in particular until you interact with it, then it's wave function changes to a more narrow shape showing the increased probability that the particle is located where you interacted with it. There are lots of other wave functions, however, that do not have space or position in them, such as momentum or spin orientation or the like. If there was one thing about QM that most people get wrong (often because teachers either themselves don't get this, or don't make it explicit enough) is that quantum mechanics abandons the notion that a fundamental particle is an object in any sense we understand the term "object" to mean. Some properties of quantum particles are definite and well-defined, like electric charge and spin magnitude and things like that, but other properties (including position and momentum) are not well defined, meaning those values can only be described by giving the probability of finding the particle with that value for the measurement. If we graph all of those probabilities on a coordinate system, where the Y axis is defined as the probability of finding the particle with that value, and the amplitude is just the maximum probability of finding the particle with that value. The mathematics of the graph we draw obeys the mathematical rules of wave mechanics, which is why it is called a wave function. But again, it isn't a wave in the real world. It's a wave in probability space, which is a mathematical construct where the property being measured is plotted on some of the axes, and one of the axes is a probability. (This is a massive oversimplification, and ignores the difference between, for example Ψ and Ψ2 and a WHOLE lot of messy math, but it captures the spirit, which is all we need here). I highly recommend a few channels on YouTube that explain this even better than I can through text are Science Asylum (Nick Lucid) and 3Blue1Brown (Grant Sanderson). Science Asylum does a fantastic job of explaining complex physics phenomena in a short, informative, and easy to digest way (pretty much the OPPOSITE of Wikipedia articles on the subject) while 3Blue1Brown covers complex mathematics in a slow, methodical, but still fantastically clear manner that also makes these things easy to understand. This video that Science Asylum did on the Wave Function is probably most germane to our discussion, but his entire series on QM would be useful. I don't have a specific 3Blue1Brown video to recommend on this direct topic, but he's done lot of videos the mathematics useful to understanding QM (such as this video on the uncertainty principle [22] which starts off his whole series on the Fourier transform, which is a mathematical tool with many wide-ranging uses, but which is SUPER important to understanding the mathematics of QM). I hope that helps some. --Jayron32 13:19, 29 April 2020 (UTC)[reply]


Like many simple questions in physics, there is a long and convoluted answer! To summarize shortly, whomever spoke of the photon's amplitude was being sloppy and imprecisely using terminology - and this sort of nonsense is very common amongst practicing physicists, because as a community, they've generally proven to themselves that they can be precise when they need to be, and they know that they don't usually need to apply that precision, because being excruciatingly correct all the time becomes very tiresome.
So - to the question: what is the amplitude of the photon?
To recite the rote-memorized answer, that would be a quite trivial question! Why, the amplitude of "the wave function", of course.
Now, the thing that's funny about quantum physics is that the books all speak in grandiose terms about the wave function; they have a special equation for the function; and they even have a special-purpose symbol, , which is exclusively reserved to represent the function. And if you read any book on the topic, the amplitude of is a scalar; and it is an abstract quantity that can be used to predict the probability and the time-evolution of measuring some other physical observable. But what is it?
If you read a little deeper, and learn what the function is, you'll discover that it's actually unique to every single physical system. There are actually many different wave functions; the part that is common to all of them is that they must satisfy certain mathematical and physical requirements.
In the case of the quantum-mechanically-correct description of the photon, the actual equation that describes the wave function is not so surprising: it is derived from the very same relationships that describe the classical electromagnetic wave; and that wave is easily represented using the classical wave equation of conventional electrodynamics. That wave is a pair of coupled vector-quantities; the two components - a magnetic field and an electric field - have position and direction, but they have no extent.
By convention, we often simply work with the amplitude of the electric field and we ignore the amplitude of the magnetic field; but it doesn't really matter, because we can equally convert to calculate the amplitude of the magnetic field. Because the two fields are related by a very well-behaved governing-equation, we can easily switch between electric- and magnetic- field amplitude; this is simply a change of units, with a little extra-special mathematical care in the case the wave is propagating inside an imperfect material.
To make the equations for these amplitudes quantum-mechanically-correct, we just need to make sure that the time-evolution of the system abides by any quantized interactions; but in the case of the electromagnetic wave in a vacuum, there's no change from the classical case: the photon is the quantum particle, and its quantum mechanical wave function is the classical electromagnetic wave function.
The extra work to manipulate the equation so that it looks like the Schrödinger equation is really just a rearrangement of variables - and when you succeed in doing that, you've simply rearranged the same thing into a format that is particularly inconvenient for expressing macroscopic interactions between the photon and the outside world. But that form is useful for describing special cases in physics - things like photon-material interactions; or making statistical predictions about the probabilistic behaviors of individual photons; and so on. For those cases, the amplitude of is used to predict the amplitude of E and B (the electric field and the magnetic field).
And of course, because the actual values of those field amplitudes are themselves a probabilistic attestation deduced from the amplitude of , we expect that should evolve predictions that, over time, change in a manner that is statistically indistinguishable from the time-evolution of the amplitudes of E and B, in other words, the classical wave equation.
Nimur (talk) 13:27, 29 April 2020 (UTC)[reply]
Nimur's answer is also really good here, as it draws comparison to "classical" wave mechanics and quantum mechanics. I just want to point out that his analogy between the the classically defined EM wave equation and the quantum wave function is really useful here, but maybe not in the direction one thinks; for example, when one asks "what is waving" in the EM wave, we say "the electromagnetic field". This is similar to saying that the thing that is waving in an ocean wave is the ocean, except that the ocean is a real physical stuff we can pick up and touch and is an object. The electromagnetic field is not a stuff. Like all fields (classical or quantum) it is a mathematical construct. A field is just a set of numbers (which can be scalar, vector, or tensor) that we attach to space itself, describing a specific property that space has. The "manipulation of variables" and the other things Nimur talks about relating the quantum wave function to the EM wave itself are just a set of mathematical transformations. Just as you can do math to convert one function to another (for example, the way that the exponential function eix can be used to convert between circular motion and wave motion, there are also trivial mathematical tools we can use to convert between EM waves in the EM field to quantum wave functions in probability space. Such mathematical tools change our perspective on a phenomenon, but don't fundamentally change the phenomenon itself). So, when we say "what is waving" in an EM wave, it's the values we assign to the various points in space that we call the EM field, and when we say "what is waving" in the quantum wave function, it's the probability of the particle having the values in question. And because those functions are describing the same phenomenon from different perspectives (both describe light), there must be some mathematical tool to relate them to each other. --Jayron32 13:55, 29 April 2020 (UTC)[reply]
Thank you, Jayron. Your post has helped me to realize something: I am just assuming that everybody already knows what electric fields and magnetic fields are. Of course, if our readers are not intimately familiar, they can review those articles.
If I may coopt Jayron's terminology - and simplify by glossing some of the details - the "thing" that is "waving" is the Electric field (and the B-field, per our earlier discussion). The E-field is not "stuff." It is a set of numbers that tell us what force would be felt by a charged particle if it were at a specific place. Those numbers are what are waving up and down. If we had a way to measure those numbers, we could see them fluctuating in a more-or-less perfectly sinusoidal fashion. But the only way we can measure those numbers is to place a test-particle at some specific position, and watch how it moves.
The really tricky part is that if we actually put a charged particle there, the waving numbers that tell us what force the particle should feel would change because they would interact with the charged particle; it would have its own fields; and it would also be moving as the wave interacts with it. So these wave-equation representations are mathematical idealizations - they help us make useful predictions, and they only make helpfully-valid predictions when we consider statistically-large numbers of individual particles, so long as we are willing to ignore the effects of any individual particle.
It isn't necessarily obvious - great scientists became famous for finally realizing this very subtle detail! - but the E- and B- fields are deeply deeply related to the photon. Early physicists described electricity, and magnetism, and light; and for a lot of centuries, we thought of them as three separate things; but ... we now understand that all of them are actually the exact same thing under different conditions. Photons interact with E- and B- fields - but even more importantly, photons are actually made of E- and B- fields. There's nothing else inside of a photon except those fields - and those fields are not made of "stuff"! And if you're a real mathematical hot-shot with access to a good book, you can play some advanced vector-calculus-trickery to demonstrate that the E-field and the B-field are the exact same thing, too: they're not merely related or coupled fields - they're the same exact darned field. And this is the equally important bit, that's less-often shouted at students: if photons are made of E- and B- fields, then .... every E- or B- field you can conceive can be expressed as a photon. It might be a pathologically poorly-behaved photon - it might have a ludicrously useless wavelength; but ... there you have it. Photons-the-size-of-mountains, emitted by electric-wires-strung-between-peaks.
So if you're trying to figure out what "stuff" is "waving" when an electromagnetic wave ... "waves"... well, we can quickly find ourselves traveling down the rabbit-hole of physical definitions: what is "stuff"? Which physics-ese techno-jargon word corresponds to the plain English word "stuff"? (Matter? Mass? Momentum? Quantum state exclusivity?) And I am pretty sure our only conclusion will be that natural human languages are not really expressive enough to describe some of the physical realities unless we throw the weight of a lot of words at it.
Nimur (talk) 17:22, 29 April 2020 (UTC)[reply]
All of that being said, I really do recommend the OP watches the videos I recommended. Seeing someone explain something in a video format, with pictures and animations, can be a lot more enlightening than reading the same information. --Jayron32 18:15, 29 April 2020 (UTC)[reply]
The energy and momentum of a Photon which is the elementary particle of the electromagnetic field depend only on its frequency or inversely, its wavelength. Increasing the amplitude of a beam of light or radio wave doesn't create "stronger" or higher-amplitude photons, it just creates more of them. DroneB (talk) 21:39, 29 April 2020 (UTC)[reply]

Thank you tremendously folks, I hadn't anticipated such a thorough set of responses. To Jayron32's suggestion - I'm quite familiar with 3Blue1Brown and will surely venture down that particular rabbit hole along these lines, and have not heard of Science Asylum but will give it a proper go as well. I appreciate everyone's helpful explanations here. Opossum421 (talk) 11:12, 30 April 2020 (UTC)[reply]

Rooibus

Where can I buy a rooibus plant to grow in my garden?99.145.194.98 (talk) 19:42, 29 April 2020 (UTC)[reply]

Possibly you mean the Rooibus tea plant cultivated in South Africa. The American Herbal Products Association has a website that may help you locate sources and there is an Australian supplier. DroneB (talk) 21:22, 29 April 2020 (UTC)[reply]
Postage to and from Australia is very delayed at the moment due to limited international flights, so if you are in the USA, buy from USA. Graeme Bartlett (talk) 23:56, 29 April 2020 (UTC)[reply]
To import plants or seeds from abroad you need a phytosanitary certificate or a small lots permit, to make sure you are not bringing non-native pests or pathogens into the US. Please check USDA APHIS website for what documentation is necessary in your case, and how to apply for it properly. Best regards, Dr Dima (talk) 06:19, 30 April 2020 (UTC)[reply]

April 30

Weider weight bench

Are there Weider olympic weight benches available anywhere?99.145.194.98 (talk) 05:28, 30 April 2020 (UTC)[reply]