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1948 Davis Cup

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1948 Davis Cup
Details
Duration22 April – 6 September
Edition37th
Teams29
Champion
Winning nation United States
1947
1949

The 1948 Davis Cup was the 37th edition of the most important tournament between national teams in men's tennis. 25 teams entered the Europe Zone, and four teams entered the America Zone. Pakistan and Turkey made their first appearances in the competition.

Australia defeated Mexico in the America Zone final, and Czechoslovakia defeated Sweden in the Europe Zone final. Australia defeated Czechoslovakia in the Inter-Zonal play-off, but fell to defending champions the United States in the Challenge Round. The championship was played at the West Side Tennis Club in Forest Hills, New York, United States on 4–6 September.[1][2][3]

America Zone

Draw

Semifinals
8–25 July
Final
6–8 August
Havana, Cuba
 Australia5
Mexico City, Mexico (clay)
 Cuba0
 Australia4
Montreal, Canada (grass)
 Mexico1
 Canada1
 Mexico4

Final

Mexico vs. Australia


Mexico
1
Centro Deportivo Chapultepec, Mexico City, Mexico [4]
6–8 August 1948
Clay

Australia
4
1 2 3 4 5
1 Mexico
Australia
Armando Vega
Bill Sidwell
6
2
6
8
6
3
4
6
5
7
 
2 Mexico
Australia
Gustavo Palafox
Adrian Quist
4
6
1
6
4
6
     
3 Mexico
Australia
Gustavo Palafox / Armando Vega
Geoff Brown / Colin Long
0
6
2
6
2
6
     
4 Mexico
Australia
Armando Vega
Adrian Quist
9
7
6
4
6
2
     
5 Mexico
Australia
Francisco Guerrero Arcocha
Bill Sidwell
1
6
4
6
2
6
     

Europe Zone

Draw

Template:32TeamBracket-Compact-info

Final

Czechoslovakia vs. Sweden


Czechoslovakia
4
Prague, Czechoslovakia [5]
27–29 July 1948
Clay

Sweden
1
1 2 3 4 5
1 Czechoslovakia
Sweden
Vladimír Černík
Torsten Johansson
6
4
4
6
6
3
6
3
   
2 Czechoslovakia
Sweden
Jaroslav Drobný
Lennart Bergelin
6
0
6
3
7
5
     
3 Czechoslovakia
Sweden
Vladimír Černík / Jaroslav Drobný
Lennart Bergelin / Torsten Johansson
6
2
6
1
6
2
     
4 Czechoslovakia
Sweden
Vladimír Zábrodský
Torsten Johansson
3
6
6
3
2
6
3
6
   
5 Czechoslovakia
Sweden
Ferdinand Vrba
Börje Fornstedt
6
3
6
1
6
3
     

Inter-Zonal Final

Australia vs. Czechoslovakia


Australia
3
Longwood Cricket Club, Boston, MA, United States [6]
19–22 August 1948
Grass

Czechoslovakia
2
1 2 3 4 5
1 Australia
Czechoslovakia
Adrian Quist
Vladimír Černík
6
2
13
11
6
0
     
2 Australia
Czechoslovakia
Bill Sidwell
Jaroslav Drobný
6
3
6
2
9
11
14
12
   
3 Australia
Czechoslovakia
Geoff Brown / Colin Long
Vladimír Černík / Jaroslav Drobný
8
10
6
4
3
6
4
6
   
4 Australia
Czechoslovakia
Adrian Quist
Jaroslav Drobný
8
6
6
3
16
18
3
6
5
7
 
5 Australia
Czechoslovakia
Bill Sidwell
Vladimír Černík
7
5
6
4
6
2
     

Challenge Round

United States vs. Australia


United States
5
West Side Tennis Club, Forest Hills, NY, United States [3]
4–6 September 1948
Grass

Australia
0
1 2 3 4 5
1 United States
Australia
Frank Parker
Bill Sidwell
6
4
6
4
6
4
     
2 United States
Australia
Ted Schroeder
Adrian Quist
6
3
4
6
6
0
6
0
   
3 United States
Australia
Gardnar Mulloy / Bill Talbert
Colin Long / Bill Sidwell
8
6
9
7
2
6
7
5
   
4 United States
Australia
Ted Schroeder
Bill Sidwell
6
2
6
1
6
1
     
5 United States
Australia
Frank Parker
Adrian Quist
6
2
6
2
6
3
     

References

  1. ^ Bud Collins (2010). The Bud Collins History of Tennis (2nd ed.). [New York]: New Chapter Press. pp. 495–496, 499. ISBN 978-0942257700.
  2. ^ Max Robertson (1974). The Encyclopedia of Tennis. London: Allen & Unwin. p. 384. ISBN 0047960426.
  3. ^ a b "United States v Australia". daviscup.com.
  4. ^ "Mexico v Australia". daviscup.com.
  5. ^ "Czechoslovakia v Sweden". daviscup.com.
  6. ^ "Australia v Czechoslovakia". daviscup.com.