Chakapuli

Chakapuli
Type	Stew
Main ingredients	Lamb or veal, onions, tarragon leaves, cherry plums, dry white wine, potatoes, tarragon leaves, herbs, garlic
	Media: Chakapuli;

Chakapuli (Georgian: ჩაქაფული) is a Georgian^[1]^[2]^[3]^[4] stew. It is considered to be one of the most popular dishes in Georgia.

It is made from lamb chops or veal, onions, tarragon leaves, cherry plums or tkemali (cherry plum sauce), dry white wine, mixed fresh herbs (parsley, mint, dill, cilantro), garlic and salt.^[5]

References

^ Darra Goldstein, The Georgian Feast: The Vibrant Culture and Savory Food of the Republic of Georgia, p. 87
^ Tim Burford, Georgia, p. 74
^ Семенова С.В. Грузинская кухня, p. 16
^ Любомирова К. Постные блюда из мультиварки, p. 14
^ "Georgian Recipes: Chakapuli". Georgia About. Retrieved 6 March 2015.

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[1] Darra Goldstein, The Georgian Feast: The Vibrant Culture and Savory Food of the Republic of Georgia, p. 87

[2] Tim Burford, Georgia, p. 74

[3] Семенова С.В. Грузинская кухня, p. 16

[4] Любомирова К. Постные блюда из мультиварки, p. 14

[5] "Georgian Recipes: Chakapuli". Georgia About. Retrieved 6 March 2015.

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See also

References