United States presidential election in New York, 1852

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United States presidential election in New York, 1852

← 1848 November 2, 1852 1856 →

  Franklin Pierce by Brady.jpg Winfield Scott by Fredricks, 1862.jpg
Nominee Franklin Pierce Winfield Scott
Party Democratic Whig
Home state New Hampshire New Jersey
Running mate William R. King William Alexander Graham
Electoral vote 35 0
Popular vote 262,083 234,882
Percentage 50.18% 44.97%

President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

The 1852 United States presidential election in New York took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose 35 representatives, or electors to the Electoral College, who voted for President and Vice President.

New York voted for the Democratic candidate, Franklin Pierce, over the Whig Party candidate, Winfield Scott. Pierce won the state by a margin of 5.21%.

Results[edit]

United States presidential election in New York, 1852[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Franklin Pierce of New Hampshire William Rufus DeVane King of Alabama 262,083 50.18% 35 100.00%
Whig Winfield Scott of New Jersey William Alexander Graham of North Carolina 234,882 44.97% 0 0.00%
Free Soil John Parker Hale of New Hampshire George Washington Julian of Indiana 25,329 4.85% 0 0.00%
Total 522,294 100.00% 35 100.00%

References[edit]

  1. ^ "1852 Presidential General Election Results - New York". U.S. Election Atlas. Retrieved 24 December 2013.