United States presidential election in Missouri, 1996
|Elections in Missouri|
The 1996 United States presidential election in Missouri took place on November 5, 1996 as part of the 1996 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for President and Vice President.
Missouri was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 47.54% to 41.24% by a margin of 6.3%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third with 10.06% of the popular vote. Since 1904, this state has been carried by the winner of the presidential election, with the exceptions of the elections of 1956, 2008, and 2012. This election is the most recent in which Missouri voted for the Democrat.
|United States presidential election in Missouri, 1996|
|Party||Candidate||Running mate||Votes||Percentage||Electoral votes|
|Democratic||Bill Clinton (incumbent)||Al Gore||1,025,935||47.54%||11|
|Republican||Robert Dole||Jack Kemp||890,016||41.24%||0|
|Reform||Ross Perot||Patrick Choate||217,188||10.06%||0|
|U.S. Taxpayer||Howard Phillips||Herbert Titus||11,521||0.53%||0|
|Libertarian||Harry Browne||Jo Jorgensen||10,522||0.49%||0|
|Natural Law||Dr. John Hagelin||Dr. V. Tompkins||2,287||0.11%||0|
|Write-in||Ralph Nader||Winona LaDuke||534||0.02%||0|
|Write-in||Charles Collins||Rosemary Giumarra||62||0.00%||0|