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I'm presuming warning flares fired prior to the explosion itself? Or part of the testing process? [[User:Bobby P Chambers|Bobby P Chambers]] ([[User talk:Bobby P Chambers|talk]]) 15:10, 2 January 2011 (UTC) [[File:Operation_Teapot_-_Unidentified.jpg|thumb]]
I'm presuming warning flares fired prior to the explosion itself? Or part of the testing process? [[User:Bobby P Chambers|Bobby P Chambers]] ([[User talk:Bobby P Chambers|talk]]) 15:10, 2 January 2011 (UTC) [[File:Operation_Teapot_-_Unidentified.jpg|thumb]]

:According to [http://chemistry.about.com/od/photogalleries/ig/Nuclear-Tests-Photo-Gallery/Operation-Teapot-Test.htm this site], "The lines that you see in this and several other photos are vapor trails of [[sounding rocket]]s." -- [[Special:Contributions/119.31.126.66|119.31.126.66]] ([[User talk:119.31.126.66|talk]]) 15:57, 2 January 2011 (UTC)

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December 29

what makes tuning fork prongs oscillate oppositely?

I really like this answer: http://in.answers.yahoo.com/question/index?qid=20100308050035AArgLTA But I don't get one thing. What ensures that the two prongs will oscillate in an exactly inverse way? Naively, I'd think the chances of that happening by chance are infitessimal compared with the chances of their not oscillating at just inverse frequencies when struck.... 87.91.6.33 (talk) 02:11, 29 December 2010 (UTC)[reply]

p.s. am I also riht that the fork could just as easily have 4, 6, 8, or 12 prongs? In this case, half of the prongs would oscillate one way and half the other??? (inverse frequency) what ensures this?? 87.91.6.33 (talk) 02:11, 29 December 2010 (UTC)[reply]
For the 1st question, my guess is that the "handle" creates a node. This explains why the two prongs oscillate in opposite directions, because they are really one bent prong with a handle in the middle. Not sure about more then 2 forks, I suppose it's possible but would depend on specifically how it is designed. Vespine (talk) 03:34, 29 December 2010 (UTC)[reply]
If they didn't start out synchronized, they will rapidly synchronize themself. Watch some of these videos for some examples. Ariel. (talk) 06:41, 29 December 2010 (UTC)[reply]
I think the answer to this is quite simple: the tuning fork starts out in some combination of equal-phase and opposite-phase vibration, but the equal-phase part is quickly damped out by the mechanism described by that Yahoo answerer. You'll always end up with mirror-symmetric oscillation eventually as long as a mirror-symmetric oscillation mode exists and you started out with at least some energy in that mode. I see no reason why it couldn't also work with 3, 5, ... prongs, since those shapes can oscillate symmetrically too. The oddly titled article Odd sympathy discusses this. I'm not sure I understand what happens to the metronomes on the soda cans, but I think it's somewhat different. -- BenRG (talk) 11:32, 29 December 2010 (UTC)[reply]
The modal analysis article is worth linking. Nimur (talk) 14:19, 29 December 2010 (UTC)[reply]

Why do we fear or 'over react' when something falls from our hand?

Why do we fear or 'over-react' when something falls from our hand (accidentally)? - anandh, chennai —Preceding unsigned comment added by 125.21.50.214 (talk) 04:43, 29 December 2010 (UTC)[reply]

Because we'd rather it didn't break when it hits the floor? --Jayron32 04:44, 29 December 2010 (UTC)[reply]
I once read that when a woman drops something she tends to throw her hands back and step back, as if avoiding anything further to do with the falling object at that moment, while a man will use all his limbs in a seemingly desperate attempt to slow the object in its fall to the floor. Some random original research would seem to support that view, but I have no idea if it's more broadly true. HiLo48 (talk) 05:48, 29 December 2010 (UTC)[reply]
I suspect whoever wrote that was completely making things up, either based on a small selection of people they had known to drop things, or just because it matched how they thought the world worked. It doesn't fit with any of my personal experience or observations, nor does it seem at all consistent with anything I have read on the actual science of gender differences. Did you, perhaps, read it in a fiction book? 86.164.67.8 (talk) 17:41, 29 December 2010 (UTC)[reply]

Not just breakables. We do have a jerk when things slip out of our hands. —Preceding unsigned comment added by 125.21.50.214 (talk) 05:50, 29 December 2010 (UTC)[reply]

It probably has something to do with dropping babies. Sean.hoyland - talk 12:16, 29 December 2010 (UTC)[reply]

It may be a counterpart to an impulse a highly developed capacity to grasp. The hands are used to hold onto something, and they do that under a wide variety of circumstances and over extended periods of time. The hands of humans are very well developed in this area and there is probably complex mental functioning supporting the grasping functions of the hands. The realization that there is a failure in that function probably causes complex mental reactions. Somehow, I would guess, that leads to overreaction, or fear. Bus stop (talk) 12:25, 29 December 2010 (UTC)[reply]
The answer to this, I think, is actually quite complex. The mechanism is actually a way of speeding reaction times, but the way we perceive it is shaped by some special brain mechanisms. Some of the factors that come into play are discussed in the article Neuroscience of free will, especially the section relating to reaction times. Looie496 (talk) 16:36, 29 December 2010 (UTC)[reply]
It think it is a VERY good question, I would love to read a study on this, my emotional state when I drop something insignificant is, for 1 or 2 seconds, completely an over-reaction, given the non-gravity of the situation. Maybe Sean or Bus are onto something here. --Lgriot (talk) 14:15, 30 December 2010 (UTC)[reply]
If it is a food item and you are a proto-human you may lose that food item: a fellow of your own species may pick it up and run away. Bus stop (talk) 19:56, 30 December 2010 (UTC)[reply]
Totally OR: Remnant from our tree-dwelling monkey-like ancestors? They evolved a fear of dropping things, because it would very frequently mean you loose it forever, and the only things a tree dwelling creature would we have in their hands is either valuable food, or ideed as mentioned above, a baby. Droping any of of the 2 would have either serious or extremely serious evolutionary consequences? --Lgriot (talk) 09:35, 31 December 2010 (UTC)[reply]
This is interesting:
Contrary to popular opinion, humans - homo sapiens - are not the only primates possessing opposable thumbs. Chimpanzees and monkeys can oppose the thumb to the index digit. What makes the human hand unique in the animal kingdom is the ability of the small and ring fingers to rotate across the palm to meet the thumb, owing to a unique flexibility of the carpometacarpal joints of these fingers, down in the middle of the palm. This is referred to as "ulnar opposition" and adds unparalleled grip, grasp, and torque capability to the human hand. This feature developed after the time of Lucy, a direct human ancestor, who lived about 3.2 million years ago.
And from the same source:
About a quarter of the motor cortex in the human brain (the part of the brain which controls all movement in the body) is devoted to the muscles of the hands. This is usually illustrated with a drawing of a human figure draped over the side of the brain, body parts sized proportional to the amount of brain devoted to their movement, referred to as a homunculus - as illustrated in this drawing from Dr. Wilder Penfield's monograph "The Cerebral Cortex of Man." (the illustration is at that source)
Inadvertently dropping something from one's hands requires an immediate response under certain circumstances.
WP:Original Research: Due to the complexity of the hands and their functions, the response is automatic, thus we overeact when the dropped object is unimportant. Bus stop (talk) 14:29, 31 December 2010 (UTC)[reply]
  • The comment above about men-v-women on this issue reminds of an incident from my own life. A female coworker and I found ourselves in a van with a flat tire. An older Chevy Astro as I recall. I jacked it up and took the flat off. Right as I did that the jack sank suddenly into the soft earth and the van began to tilt and was seemingly going to fall. I grabbed the edge of the wheel well and pulled for all I was worth, and began urging my co worker to retrieve the jack and re-position it. She had already backed up to a safe distance outside the path of the tilting van and laughed at the very suggestion that I could hold this van up while she crawled underneath it and recovered the jack. She was probably right, and I would have hated to crush her skull or spine that day, but it rather shattered my illusion of being Superman. Beeblebrox (talk) 00:01, 2 January 2011 (UTC)[reply]

What kind of holly?

The holly and the icy

What kind of holly is this? I never realised that there were multiple holly species until this evening, when I discovered that there were lots of different categories at Commons for different species of holly. Nyttend (talk) 05:04, 29 December 2010 (UTC)[reply]

I'm not sure we can tell from that one picture. There are literally hundreds of different species and/or hybrids of Holly, and many are likely to be indistinguishable execpt by careful, direct, examination by a knowledgeable botanist. See Holly#Selected_species for an idea of the problem. Browsing through several of these that have pictures in the articles, I can't find much to distinguish them either from each other, or from your picture. --Jayron32 05:17, 29 December 2010 (UTC)[reply]
Hmm. Sorry to have asked an unanswerable question; thanks for trying. Nyttend (talk) 16:16, 29 December 2010 (UTC)[reply]

Dark energy and antimatter

Hello. Is antimatter attracted or repelled by dark energy? Is there anything in the universe which is attracted by dark energy? Thanks in advance.--Leptictidium (mt) 11:32, 29 December 2010 (UTC)[reply]

Dark matter interacts with other matter (including antimatter) gravitationally. This interaction is always attractive. --Wrongfilter (talk) 12:58, 29 December 2010 (UTC)[reply]
Dark energy (not dark matter) is basically another way of looking at the metric expansion of space. As such, it's a property of the vacuum, rather than something to do with matter, so normal matter vs. antimatter is irrelevant.
The consensus among physicists is that the gravitational interaction of antimatter is attractive, although that hasn't actually been experimentally confirmed yet. But again, that's actually irrelevant to a discussion of dark energy. Red Act (talk) 14:46, 29 December 2010 (UTC)[reply]
Oh dear. Sorry, I misread. --Wrongfilter (talk) 15:02, 29 December 2010 (UTC)[reply]
I'd like to add that it is unknown whether or not dark energy is a property of the vacuum. That is a leading theory, but alternative theories (such as quintessence) would allow the repulsive effects of dark energy to be associated with some new type of particle. Since we don't really understand what causes dark energy, it is safe to say that there are lots of possible explanations. Some are more plausible than others. Dragons flight (talk) 18:34, 29 December 2010 (UTC)[reply]

How much damage would a missile do?

Let's say a Hsiung Feng IIE missile was fired into the middle of Central, Hong Kong at rush hour. How much damage would it do? How big would the crater be? How many people would it kill? (A dozen? Hundreds?) 122.61.218.145 (talk) 12:04, 29 December 2010 (UTC)[reply]

It depends very much on the actual warhead. With a dead weight, maybe around a dozen. With a HE warhead, I'd guess hundreds. In both cases, there would be a very large spread of possible outcomes. If you assume WMD loads, the numbers can become much higher. --Stephan Schulz (talk) 14:02, 29 December 2010 (UTC)[reply]
With due respect, the OP's scenario is worrying about cruise-missile targeting from the vantage point of "concerned citizen," and not from that of a "geopolitical strategist." Most reliable references on the strategic implications of cruise-missiles focus on their cost-benefit analysis; and most rational strategists would opt to target airports and air-bases, not busy city streets. Cruise Missile Proliferation in the 1990s discusses details and specifications some of the various missile capabilities known to exist in various countries. The Cruise Missile Challenge, a policy report published by independent agency CSBA, gives a good overview of cruise missile politics, cost, and even discusses their potential strategic use in the Taiwan Strait conflict. Bear in mind, cruise missiles are really expensive - and Taiwan doesn't have many of them; so strategically, the most significant targets for them would be military airfields (where a single strike could incapacitate hundreds of millions of dollars of enemy aircraft). Airbase vulnerability to conventional cruise-missile and ballistic-missile attacks, published by the infamous RAND Corporation, provides a stunningly (and frighteningly) detailed scenario of potential damage (and vulnerability of) an American air-base to an enemy cruise-missile attack; and it lays out the cost-benefit analysis of strategic and tactical missile strikes. Regarding blast range, collateral damage, casualties, and targeting effectiveness, of course that sort of detail would be highly confidential; but you can easily estimate the power of a 200 kg warhead and the probability of landing on a crowd of any particular density of people-per-square-meter. (But you can see maps, diagrams, and blast-radii in that altogether terrifyingly descriptive RAND book). Ultimately, keep in mind that military use of cruise-missiles against civilian targets is both expensive and geopolitically stupid - the world does not look kindly on the use of powerful technological weaponry against civilian targets. Taiwan would be unwise to expend its very limited stockpile of tactical or strategic missiles against a civilian target; each missile fired at a civilian target would clearly aggravate their adversary; and simultaneously, it would do little to impede the Chinese military capability for retaliation. Nimur (talk) 14:10, 29 December 2010 (UTC)[reply]
Also, deliberately attacking the civilians of your enemy is prohibited by the Fourth Geneva Convention (1949). You can, say, attack the Ministry of War's building, even if doing so will cause civilian casualties, but you can't launch attach that will solely cause civilian deaths. CS Miller (talk) 15:29, 29 December 2010 (UTC)[reply]
When was the last time a world-class business city was attacked by a state's armed forces using big-enough-weapons? The city must be a key player in international business (e.g., NY, London, Tokyo, HK ...). Did it ever happen after WW2? The Chinese civil war (-1949) was not a war between two countries. Berlin was only denied land-based access by the Soviets. Seoul was not an international business city at the time of Korean war. 1950s and 1960s Saigon might have been a large city however Vietnam as a French colony was not very "international". Beirut has always been a regional city. The 9/11 attack was not ordered by any country. Baghdad certainly was not very international. -- Toytoy (talk) 18:12, 29 December 2010 (UTC)[reply]
What's a 'world-class business city' ? Sean.hoyland - talk 18:15, 29 December 2010 (UTC)[reply]
I can't define it. However, it must have a certain percentage of investments from many major 1st world countries. As a result, if you attack this city, investors could get very angry at you. You not only make the victim country very angry, but you also make many other 1st world countries very very unhappy. Let's say I bombed a small town in Kansas. People around the world may never heard of that town (population 32). They do not get very angry. But if I bombed London or Paris, people all over the world knew the city, many people have money in these cities, they get very very very angry. -- Toytoy (talk) 18:21, 29 December 2010 (UTC)[reply]
I asked because 'When was the last time a world-class business city was attacked by a state's armed forces using big-enough-weapons?' is quite an interesting question that I don't know the answer to....um...Kuwait City, Belgrade...maybe...I'm struggling. Sean.hoyland - talk 18:35, 29 December 2010 (UTC)[reply]

The Hsiung Feng IIE's modern 200 kg high explosive payload might be roughly comparable to the WW2-era 980 kg Amatol payload of the German V-2 missile. The worst loss of life in a single V-2 attack was 160 killed and 108 seriously injured and a modern reconstruction (see article) demonstrated that the V2 creates a crater 20 m wide and 8 m deep. Cuddlyable3 (talk) 22:19, 29 December 2010 (UTC)[reply]

Note of course modern Hong Kong in many parts has a much higher population density then pretty much anywhere in wartime England I would guess Nil Einne (talk) 19:55, 30 December 2010 (UTC)[reply]

Elipitical Orbit

I would like to know whether the orbit of a planet/satellite become an elipitical orbit if its tangential velocity is reduced or increased beyond the confines of a circular orbit. References preferable. --Tyw7  (☎ Contact me! • Contributions)   Changing the world one edit at a time! 12:35, 29 December 2010 (UTC)[reply]

Yes it does (in both cases), at least as long as an increase in velocity is not so large as to make the orbit unbound (i.e. parabolic or hyperbolic). In the spherically symmetric gravitational field of the central body any (bound) orbit is periodic, i.e. the satellite has to return to its original position. If you decrease the velocity, that point will become the apocenter (i.e. the point farthest from the central body) of the elliptical orbit, if you increase the velocity it will become the pericenter. --Wrongfilter (talk) 12:57, 29 December 2010 (UTC)[reply]
Regarding references: I highly recommend the book To Rise From Earth, which provides a straightforward explanation of orbital mechanics that is accessible to any interested reader (even if they don't have a firm background beyond basic algebra). This book is intended to introduce the concepts and basic mathematics of spaceflight without requiring a full-blown degree in astronautics. It is suitable for anyone with at least a junior-high or high-school level of algebra, and claims to use "no equations" to describe orbital mechanics (though I seem to recall a few). There are also plenty of textbooks that study this subject in greater details, if you do have at least some background in basic calculus and physics. And if you are interested in professional grade space navigation, NASA provides DESCANSO, a compendium website of educational and technical resources, including free textbooks, for Deep Space Communications and Navigation systems that will hold nothing back on the "details." (After all, if you want to point your communications antenna at an interplanetary probe, you had better calculate its orbit exactly - no "approximations"). Nimur (talk) 13:41, 29 December 2010 (UTC)[reply]
Interacting objects in orbit and orbital resonances may increase the eccentricity of both orbits in proportion to their masses. Pluto and Neptune are an interesting pair. ~AH1(TCU) 17:34, 1 January 2011 (UTC)[reply]

Does cancer cause hair to fall out?

Or does the treatment like chemo cause the hair to fall out? ScienceApe (talk) 18:34, 29 December 2010 (UTC)[reply]

Chemotherapy is what causes it to fall out. thx1138 (talk) 18:41, 29 December 2010 (UTC)[reply]
Radiotherapy and many (but not all) forms of chemotherapy rely on the greater susceptibility of rapidly dividing cells to DNA damage. While the malignant cells targeted by these therapies certainly fit the bill, there are a few other places in the body where normal cells divide rapidly; it is the sensitivity of these tissues that often establishes the maximum tolerable dose for these therapies, and which is responsible for many of the side effects associated with these treatments. Quickly dividing cells in bone marrow, the lining of the gastrointestinal tract, and in hair follicles are all sensitive to DNA-damaging treatments, leading to (respectively) anemia, (some of the) nausea, and hair loss associated with certain types of cancer treatment. With radiation therapy, hair loss will only occur within the areas exposed to ionizing radiation; with systemic chemotherapy hair loss can be widespread. TenOfAllTrades(talk) 19:39, 29 December 2010 (UTC)[reply]

Animal slime?

With regards to the slime secreted by slugs/snails, frogs, fish, eels, etc. - is it all the same basic stuff, regardless of the creature that secreted it (I guess that some animals can add toxins and irritants to it)? If so, is there a an easily writeable chemical formula for this substance? --95.148.109.133 (talk) 18:54, 29 December 2010 (UTC)[reply]

The technical term is mucus, and as that article tells you, the most important components are a variety of proteins. Looie496 (talk) 19:02, 29 December 2010 (UTC)[reply]
Many animals can make mucus including some single cell protists. Glycoproteins are abundant. Graeme Bartlett (talk) 20:13, 29 December 2010 (UTC)[reply]
And as for a single chemical formula, proteins have incredibly complex chemical formulas (Beta Actin has an MW of around 42,000 If I recall). Googlemeister (talk) 15:25, 31 December 2010 (UTC)[reply]

Intelligence of a sleeping human

How intelligent is someone who's asleep, but not dreaming? While I'm at it, what about animals? — DanielLC 20:48, 29 December 2010 (UTC)[reply]

That's kinda like asking "What is the blood type of someone who's asleep". Even ignoring the fact that "intelligence" is a nebulous, unmeasurable quality to begin with. So, insofar as someone has a measurable thing called "intelligence" at all, it shouldn't be different just because they are asleep. Since someone cannot take an intelligence test while asleep (indeed, one cannot take any test while asleep) it seems a silly proposition to begin with. Animal intelligence is even more difficult to assess; we can measure animals on their ability to perform certain tasks (such as run through mazes or pfoint at pictures to get food), but exactly how or why these tasks might indicate "intelligence" is pretty difficult to assess. --Jayron32 20:56, 29 December 2010 (UTC)[reply]
You can still respond to stimuli while asleep. You can't take an IQ test, but neither can any animal except a human. Can't they still test your intelligence the same way they test that of an animal? I don't see why intelligence would be the same when you're asleep. People have been known to walk and talk in their sleep, and they certainly don't act as smart as people who are awake. — DanielLC 21:23, 29 December 2010 (UTC)[reply]
Actually, people have been known to perform highly complex activities while sleepwalking (although our article, Sleepwalking, says such claims are disputed). --Tango (talk) 21:28, 29 December 2010 (UTC)[reply]
What particular measure of intelligence do you propose? The WAIS may be difficult to administer to someone who is unconscious. As I stated, the very concept of quantifying intelligence is problematic even for humans. Its hardly a rigourous, scientific thing. This is even moreso for animals; assigning a quantity, which may not have any real meaning, to a subject which cannot even be tested for that quantity, is doubly meaningless. --Jayron32 21:29, 29 December 2010 (UTC)[reply]
And you can't test the intelligence of a sleeping animal anyway. Intelligence is not something floating around in your blood. When they talk of animal intelligence, they either talk in very large generalizations regarding the forebrains of an entire species (which you could do about humans, too, but it doesn't tell you anything surprising, asleep or otherwise) or they talk about things like problem solving, which require being awake to measure. --Mr.98 (talk) 22:29, 29 December 2010 (UTC)[reply]
I wouldn't recommend a test designed for humans. How do they compare the intelligences of animals? Can't they also do stuff like use an MRI to see what sections of the brain are being used, an other tests to see what those sections actually do?
Looks like I forgot to sign that. Isn't there supposed to be a bot for that? — DanielLC 00:39, 30 December 2010 (UTC)[reply]
"...one cannot take any test while asleep"
Not so: Multiple Sleep Latency Test, Polysomnography. Mitch Ames (talk) 01:15, 30 December 2010 (UTC)[reply]
If you included dreaming I'd say just as intelligent as the person was when awake, but with a distorted perception of reality. 82.44.55.25 (talk) 21:26, 29 December 2010 (UTC)[reply]

Sleep (see article) is clearly a period when the person does not demonstrate their intelligence. For example, the sleeper is oblivious to unexpected dangers and will not converse. However experiments in sleep deprivation show that sleeping has a rejeuvenating effect on memory whose health is essential to intelligence, see the article Sleep and memory. Higher mental activities such as learning and creativity (see articles) can also occur during sleep. A possible answer to the OP is that the sleeper's mind is liberated from its survival needs to be intelligent, conscious and coherent, but that all the mental resources to be so are present in latent form. The Autonomic nervous system continues in sleep to control essential functions such as heart rate, respiration and digestion but these are classed as evolved rather than intelligent functions. Cuddlyable3 (talk) 21:55, 29 December 2010 (UTC)[reply]

They don't show much intelligence. There's still some. — DanielLC 00:39, 30 December 2010 (UTC)[reply]
Intelligence during sleep can manifest as the creation of dreams which are full of puns, and which relate recent events to meaningful events and themes in one's history. Dreams are often forgotten within seconds of waking, but occasionally I have been able top recall dreams which would be amazing works of creative writing if done during waking hours. Edison (talk) 19:41, 30 December 2010 (UTC)[reply]
Famously, August Kekulé solved the structure of benzene in a dream. Wnt (talk) 03:00, 31 December 2010 (UTC)[reply]
Lucid dreaming implies some intelligence while asleep. Mitch Ames (talk) 03:53, 31 December 2010 (UTC)[reply]
I don't see why it needs to be lucid. The only difference between lucid dreaming and the ordinary kind is that you've figured out that you're dreaming. Knowing that fact is not a necessary condition to exercise cognition, nor to be conscious (in the sense of phenomenal consciousness).
It doesn't need to be lucid, but it does need to be dreaming. I specifically asked when you're not dreaming. — DanielLC 01:51, 1 January 2011 (UTC)[reply]
In fact I don't think it's necessary even to be dreaming. I'm pretty sure there are times that I am asleep, but both phenomenally conscious and exercising cognition. --Trovatore (talk) 03:59, 31 December 2010 (UTC)[reply]
I'm interested in the times when you're not. — DanielLC 01:51, 1 January 2011 (UTC)[reply]
Logical reasoning may be impaired during a dream. The lucidity of a dream may impact many factors you describe. ~AH1(TCU) 17:33, 1 January 2011 (UTC)[reply]

Is it a colorless gas? --Chemicalinterest (talk) 21:06, 29 December 2010 (UTC)[reply]

Apparently. For these sorts of questions about the appearance of chemical compounds, a Google search for something like oxygen difluoride appearance generally gives pretty good results. TenOfAllTrades(talk) 21:57, 29 December 2010 (UTC)[reply]
True, but it's always nice for it to be confirmed by those of us with access to the standard reference sources! Colourless gas that condenses to a pale yellow liquid. Physchim62 (talk) 15:17, 30 December 2010 (UTC)[reply]


December 30

Wormholes

From what I have heard in the past Hawking said that wormholes cannot exist because if matter gets sucked into the blackhole, it gets destroyed. So one cannot "enter" a blackhole and survive it. So what's the latest theory about it?

Also I have read in a newspaper that all blackholes leads to a new universe. Is that true?

Please explain in layman terms without complex equations.

--Tyw7  (☎ Contact me! • Contributions)   Changing the world one edit at a time! 00:04, 30 December 2010 (UTC)[reply]

Total non-expert opinion: The only way we have to test such a thing with our current level of technology is through "thought experiments." It may be decades or even centuries before we can actually know the answer to such a question with any degree of certainty. So, Hawking is probably right, but even he doesn't know for sure. Beeblebrox (talk) 00:32, 30 December 2010 (UTC)[reply]
The relevant article is Black hole information paradox. AFAIK Hawking capitulated on the point of destruction of information. Vespine (talk) 00:40, 30 December 2010 (UTC)[reply]
Yes, and also our Wormhole article says: "There is no observational evidence for wormholes, but on a theoretical level there are valid solutions to the equations of the theory of general relativity which contain wormholes." WikiDao(talk) 00:43, 30 December 2010 (UTC)[reply]
So one cannot use a blackhole (and white hole) as a shortcut because all matter entering a blackhole is destroyed and converted to energy. --Tyw7  (☎ Contact me! • Contributions)   Changing the world one edit at a time! 00:48, 30 December 2010 (UTC)[reply]
No, one can not do that because as far as we know they don't exist. There are some thought experiments where they have them, but don't confuse that with actually existing. BTW if you really could convert all matter entering a wormhole to energy that would be tremendously useful, plus you could use them for long distance communication. But in any case the difference between matter and energy is not very clear, so I don't see why a wormhole would allow one and not the other. Ariel. (talk) 01:22, 30 December 2010 (UTC)[reply]


How about whether each blackholes lead to a new universe? --Tyw7  (☎ Contact me! • Contributions)   Changing the world one edit at a time! 00:48, 30 December 2010 (UTC)[reply]

I haven't heard anything like that. But some people define the inside of a black hole as a different universe since it's isolated from its parent. Ariel. (talk) 01:22, 30 December 2010 (UTC)[reply]
So stuffs get sucks in and doesn't escape? --Tyw7  (☎ Contact me! • Contributions)   Changing the world one edit at a time! 18:44, 30 December 2010 (UTC)[reply]
Sort of. Its a bit more complex than that. In on definition, the Universe consists of all of the locations which are capable of exchanging information with each other (or places which have overlapping light cones) or something like that. The thing about black holes is that anything which crosses the event horizon is suddenly incapable of exchanging information anymore; such that inside of the event horizon is effectively "outside" of our universe, based on the above definition of The Universe. See cosmic censorship. This does NOT mean that the inside of the event horizon is a universe with galaxies and stars looking like our universe. It just means that, effectively, since it cannot exchange information with anywhere in our universe, it isn't part of our universe. --Jayron32 19:50, 30 December 2010 (UTC)[reply]
The wormhole that exists in the Schwarzschild metric (the simplest solution to Einstein's field equations including a black hole) is not an interesting wormhole because a) it disappears when you alter the metric to make it fit reality (for example, making the black hole come into being at a certain time, rather than existing for eternity into the past and future) and b) it doesn't exist for long enough for anything to cross it, even at the speed of light. There are other solutions involving wormholes that would be possible to cross, however they always require exotic matter and there is no evidence that such matter is possible. --Tango (talk) 20:16, 30 December 2010 (UTC)[reply]
A rotating black hole has a ring singularity. That would allow for the formation of a parallel universe and anything passing through it would be crushed and streched but would emerge through the white hole relatively intact. ~AH1(TCU) 17:31, 1 January 2011 (UTC)[reply]

Sugar Maple

I recently watched Subway (Homicide: Life on the Street). As Vincent D'Onofrio's character is dying, one of the last things he says is that the leaves of a sugar maple turn upward before a rain to catch the raindrops. Our article doesn't mention this so I'm wondering if anyone knows if it is true or not. Beeblebrox (talk) 00:26, 30 December 2010 (UTC)[reply]

I don't know whether or not it is actually true, but a google book search reveals that it is genuine folklore at least. SpinningSpark 01:04, 30 December 2010 (UTC)[reply]
I doubt it's true. Why would a maple want to catch water on its leafs? Plus how could it do it before the rain? Ariel. (talk) 01:18, 30 December 2010 (UTC)[reply]
(edit conflict) Here's an actual link for that: [1]
Speculation: there is often an updraft before a storm – the leaves of many trees will "turn up" in a very distinctive way preceding rain in that case, perhaps sugar maple leaves doing so are particularly distinctive...? WikiDao(talk) 01:20, 30 December 2010 (UTC)[reply]
In the UK there is a common phenomenon during summer whereby the leaves of trees appear to turn up, but in fact are showing there undersides because they are lifted by a southerly or south-westerly wind which often precedes a rain bearing atmospheric depression. Caesar's Daddy (talk) 08:39, 30 December 2010 (UTC)[reply]
It wouldn't do the tree much good if it DID have such a capability, since a function of leaves is to lose water and not absorb it. See Transpiration. Alansplodge (talk) 02:03, 31 December 2010 (UTC)[reply]
Normal leaves
during a dry period
Where I live there is a lot of Devils club. Normally they have broad, flat leaves the size of a dinner palte. When it is espescially dry these leaves can be seen to distintcly fold upwards. There must be some reason for this. If not to capture water, what would it be? Beeblebrox (talk) 19:57, 31 December 2010 (UTC)[reply]
It's possible that the change in pressure or increase in humidity before a rain storm could affect the leaves. Scientific29 (talk) 01:45, 4 January 2011 (UTC)[reply]

An unusual problem with viewing a 3D film.

There is, to my knowledge, a certain percentage of people that cannot see stereographic 3D effects - I am not among them. I am somewhat of a 3D enthusiast, I am a master of stereogram viewing (both parallel and cross-eyed) and enjoy viewing anaglyph images and autostereograms. I have seen many 3D movies in a variety of formats, including IMAX 3D and Fusion Camera system - either of which was apparently used to present the 3D in Tron: Legacy, a movie I saw just 20 minutes ago.

So you can understand why I am utterly confused by the fact that at the moment the movie was supposed to change over to 3D, I saw nothing of the sort - the image was flat. I had gone to see the film with a group of friends, and they all saw the 3D effect fine, and they are not the practical joking type. I switched my glasses with one of them during the credits and she said she saw the 3D clear as day, so it wasn't the glasses. All throughout the film I was stupefied, wondering whether we sat down in the wrong theater. I closed one eye and the other to check if the images for each were different for each eye, but they were identical. I took off the glasses and saw slight blurring like the image was focused "behind" the screen (and in fact I could see a slight 3D effect of the image "behind" the screen when I looked at the edges with the glasses on), but not the characteristic difference of blurring between near and far focused objects.

The biggest mystery was the previews, all of which were in 3D. I saw them in all their glory. The 3D effect in some of them took my breath away. And yet during the movie I saw none of that. I was very disappointed by this development.

I decided half-way through that they put the wrong version on and just enjoyed the movie. But when I told my friends it wasn't 3D they looked at me like I was crazy. I thought about it during the drive home, and I came to the conclusion that what happened to me was impossible, but it happened!

What could have caused me, someone who has never had a problem seeing 3D, to have this happen? This is the most bizarre thing that has ever happened to me, and I want to know what caused it so I can keep my sanity. Thanks in advance. Chris16447 (talk) 07:35, 30 December 2010 (UTC)[reply]

The only explanation I can think of is that your experience with autostereograms caused you to mentally cancel out the 3-D effect. As you will know, 3-D vision is processed entirely within the brain as an interpretation of what is "seen" by the eyes, so there must have been some discrepancy between what you expected to see and what was actually received by your eyes. I'm surprised that this lasted throughout the whole film. If it ever happens again, try closing your eyes for a while, then persuade yourself that the picture is just 2-D, then open your eyes and be pleasantly surprised. Dbfirs 10:24, 30 December 2010 (UTC)[reply]
An alternative (speculative) explanation is that you are colorblind and that your eyes cannot be fooled by any 3D system (there is more than one). Quest09 (talk) 13:43, 30 December 2010 (UTC)[reply]
I have not seen the movie, so this doesn't even qualify as good original research, but I was recently told by friends that are big 3D enthusiasts that the 3D effects in the movie were barely noticeable as well. 10draftsdeep (talk) 13:56, 30 December 2010 (UTC)[reply]
Colorblindless is definitely a red herring. No modern theater uses the old colored glasses; today's 3D films all employ polarization-based systems. TenOfAllTrades(talk) 14:31, 30 December 2010 (UTC)[reply]
Wouldn't that be a gray herring ? :-) StuRat (talk) 18:16, 30 December 2010 (UTC) [reply]
Even if they did use the colored 3D glasses, colorblindness wouldn't be an issue. All 3D glasses work by filtering the light that reaches your eyes so that each eye sees an image photographed from a slightly different angle. Whether you perceive those slightly different images in full color or not is irrelevant. —Bkell (talk) 14:42, 30 December 2010 (UTC)[reply]
It is just possible that, if you do not already wear spectacles for which you have been properly and recently sight-tested, and if as is probable the 3D system being used utilises directional polarisation, you have slight undiagnosed astigmatism which happens to make the image stream in one eye sufficiently less focussed as to hamper the 3D effect, especially when it is smaller. The everyday effects of mild astigmatism can be unobvious to the sufferer, whose brain compensates for them unconsciously. It might be worth your while to visit an optometrist. 87.81.230.195 (talk) 17:50, 30 December 2010 (UTC)[reply]
What I don't get is that the OP claims to have seen the previews in 3D just fine, but then couldn't see the movie in 3D. Did you change seats between the previews and the movie, Chris16447? I think the 3D effect gets worse the further from the center of the theater you are (but I'm not sure about that). WikiDao(talk) 18:14, 30 December 2010 (UTC)[reply]
The previews likely had the most extreme 3D effects, while the movie was more restrained. That's because the same level of 3D, which makes you want to see a movie in the preview, would probably make you sick, if you watched it for an hour or two. StuRat (talk) 18:18, 30 December 2010 (UTC)[reply]
They may have even made the effects more extreme in the previews. It might make sense to do so — a preview is a pretty brief encounter, and you'd want it to be eye-popping. But for a multi-hour viewing, eye-popping might turn into eye-strain too easily, at least amongst the non-enthusist population. My understanding is that it is not too hard to adjust the depth of a 3D film at different points in its production; it is not the case that it is simply "filmed in 3D" and that's the depth that it is permanently set to, I don't think. --Mr.98 (talk) 18:20, 30 December 2010 (UTC)[reply]
I think that depends on the type of movie. With a CGI movie, it's relatively simple to adjust the camera angles on an existing scene in the computer. With live-action, though, you're limited by the placement of the original cameras. Picture something behind a pole. The two cameras will hide different parts of the scene behind the pole. By moving the depth you also change what is hidden (from each eye) behind the pole. Hiding part that was visible before could probably be done simply enough with a computer, but creating the portion which was formerly hidden is a bit trickier. Your computer program would have to figure out the pattern on the wallpaper and then recreate it there, for example. To simulate this problem, place a vertical finger right in front o\f your nose, then close one eye while moving the finger forward and back, then repeat with the other eye closed. See how the portion of the room which is hidden (behind the finger) changes, in each eye ? StuRat (talk) 18:32, 30 December 2010 (UTC)[reply]
My understanding is that even in a "real life" 3D film, you can enhance or decrease the amount of depth perceived. I recall seeing something on this regarding one of the many 3D movies of awhile back; you can magnify or reduce the depth in specific scenes, and the director spends a lot of time trying to figure out what the magic depth should be for any particular scene. Obviously there are limitations to this, but I don't think you have to change it by much to have hugely different qualitative experience. --Mr.98 (talk) 20:58, 2 January 2011 (UTC)[reply]
98 may have a point. If the question-asker was sitting somewhere where the 3d effect was weak (or if his own stereo perception is weak) he still would have noticed the 3d during the previews because they're packed with crazy out-of-screen effects that you'd have to be completely stereo-blind to miss. The film, thankfully, had almost no out-of-screen gimmick shots. APL (talk) 20:17, 30 December 2010 (UTC)[reply]
Some things which can prevent the eyes from working together are:
1) Alcohol, causing the classic double vision.
2) Head injuries.
3) Obscured vision in one eye, due to dirty glasses or contacts, or "slime" on the eye. I often have this problem when I first wake up.
Also, you may just may see 3D effects less than others, so that this movie, with minimal use of 3D, was below the threshold you recognized as being 3D. StuRat (talk) 18:26, 30 December 2010 (UTC)[reply]
Obvious question : You realize that the film was only 3d 'On the grid', right? Real-world scenes were intentionally flat. (But strangely, not quite at the plane of the screen, so you needed the glasses throughout.) APL (talk) 20:17, 30 December 2010 (UTC)[reply]
I saw the movie recently and also particularly at the start and throughout other points in the movie was wondering if I was "getting" the 3d. Vespine (talk) 23:17, 30 December 2010 (UTC)[reply]
At the start there is no 3d to get. The movie is entirely 2d until Flynn enters the computer generated world of 'The Grid'. (Sort of like the color in 'The Wizard of Oz'.) APL (talk) 02:34, 31 December 2010 (UTC)[reply]
  • I am wondering if it's possible that others will develop this same "immunity" to these new 3D films, and it ultimately will end up being just a fad instead of the new way all movies are made. Personally I would find that hilarious, but I magine a lot of people in Hollywood wouldn't see it that way. Beeblebrox (talk) 20:37, 31 December 2010 (UTC)[reply]
What I think is that perhaps the movie does not contain such "intense" 3d scene as the demo. In fact, most move does not contain sharks popping out of the screen... those are usually issolated to "science" type shows/imax or short demos. Imagine the strain you would feel if the body tries, reflexively, to jerk out of the way of the oncomming animal/item/etc. Plus, I also noticed that 3d cinema films are not 3d intensive as home cinema films. --Tyw7  (☎ Contact me! • Contributions)   Changing the world one edit at a time! 08:28, 1 January 2011 (UTC)[reply]

Amount of Lanthanum Chloride in a solution.

If a solution is 40% Lanthanum chloride and 60% water, how much pure Lanthanum chloride is there in 5mL of the solution? Abbott75 12:35, 30 December 2010 (UTC)[reply]

You are going to have to know the density of this solution, which because it is strong will deviate significantly from 1. Then from your volume calculate the mass and take 40% if it. Graeme Bartlett (talk) 12:47, 30 December 2010 (UTC)[reply]
Ok, thank you. If we know that Lanthanum chloride has a density of 3.84g/cm^3 and water 0.997g/cm^3 (@ 25 degrees), is there a formula for calculation the density of the solution from these numbers? Abbott75 13:24, 30 December 2010 (UTC)[reply]
Unfortunately not; since volumes are not additive in mixing two substances, you cannot simply average the densities. The density of the resulting mixture will depend factors which cannot be directly measured, excepting by measuring the density itself. In other words, you cannot calculate or derive the density of such a mixture, you'd have to measure it directly. --Jayron32 14:50, 30 December 2010 (UTC)[reply]
I couldn't (quickly) find a figure for lanthanum chloride, but the density of a 40% lanthanum nitrate solution is 1.4477 g/cm3. So 5 ml would weigh 7.2385 g and contain 2.8954 g lanthanum nitrate. Physchim62 (talk) 15:04, 30 December 2010 (UTC)[reply]
This typical commercial product has 42% LaCl3 and a density of 1.46 g/cm3. That gives 3.07 g LaCl3 in 5 ml. Physchim62 (talk) 15:11, 30 December 2010 (UTC)[reply]

Where are the new inventions?

The last two inventions which changed my life are the cell-phone and Internet, and that was long ago. Where is my flying car? My automatic driving car? My maid robot? Quest09 (talk) 13:38, 30 December 2010 (UTC)[reply]

See flying car (aircraft), DARPA Grand Challenge, and Roomba. -- kainaw 13:46, 30 December 2010 (UTC)[reply]
Well, this Roomba is no maid robot. It is expensive, doesn't cook, doesn't clean the bathroom, doesn't make beds... It is a far cry from a maid. Quest09 (talk) 13:49, 30 December 2010 (UTC)[reply]
Then look for other domestic robots. -- kainaw 14:16, 30 December 2010 (UTC)[reply]
I'm more concerned that it's not bristling with weapons.
Follow-up: if we had a very efficient battery, which would weigh just a couple of pounds and hold lots of energy, would a (Blade Runner like) flying car be feasible? Or does the problem lies elsewhere? Quest09 (talk) 14:04, 30 December 2010 (UTC)[reply]
If that was possible, then yes, but I don't think it is, due to inherent limits on how much energy a chemical battery can store. Batteries only store a few extra electrons on atoms, and electrons weigh around 1/1836 of the weight of a proton (a little more for a neutron). So, if you use an ion engine, you propel only a tiny portion of the mass of the battery out the rear of the plane, whereas a jet fuel engine can propel 100% of the mass of the fuel out the back. Plus, the battery powered plane would have the weight of the battery to carry the whole trip, while a conventional jet plane is much lighter when it lands, having much less fuel on board. (I suppose you could arrange for a system where spent batteries are ejected with parachutes, then returned to the base and recharged, but that doesn't sound very practical, either). StuRat (talk) 20:24, 30 December 2010 (UTC)[reply]
The problem is the definition of an "invention." Historians like to say the "printing press" was one invention; but it relied on several abstract concepts (like written language), several constituent technologies (like reflowable lead metallurgy), and several "sub-inventions" (like the hinge on the lever that operated the paper-press). So, you have listed "the internet" as an invention; but in fact that "invention" really depends on many thousands of abstract concepts (like Turing completeness), constituent technologies (like low-noise radio frequency modulation), and specific sub-inventions (like ARP/RARP). Yet, you and many others consider "The Internet" a single "invention" worthy of listing next to "The Transistor" and "Fire." My point is, it's up to historians to decide which abstractions and implementations count as An Invention, and which are merely Contributing Knowledge.
Personally, I consider the Wikipedia to be an important invention. Sure, it didn't pioneer any new physics equations and it suffers from a dismal lack of flashing lightbulbs that blink; but it is an accomplishment of technology. It is a simple synthesis of pre-existing technologies to address an actual social need (the need for free, free information). I would place the accomplishment of "invention of Wiki" on the same tier as "invention of packetized data routing" (another critical technology step towards making free information possible). Futurists have dreamed about a free encyclopedia for nearly a century. Some of the greatest minds of the 20th Century predicted such a device. (H.G. Wells predicted it in 1937, Vannevar Bush predicted it in 1945, Doug Engelbart demonstrated a very simple prototype in 1968). But until very recently, these geniuses lacked several critical pieces of technology necessary to implement their technology: they did not have digital computers; cost-effective display screens; packetized information transfer; and a few specific computer programming languages (in specific, free implementations of HTTP, PHP, and SQL that make it plausible to design a machine that bidirectionally communicates encyclopedic data to and from humans). While the Wikipedia is not a new ASIC technology, nor a new computer algorithm, nor a new energy source or material, it is an invention: it is the synthesis of present technologies to address a need. Other inventions - flying-cars, laser-ignition hydrogen bombs, smart-phones - all do exist; but they fail to address an actual need for the human species. We have finally invented the Wikipedia; at present, it takes the form of an Organization with semi-centralized repositories of huge digital electronic computers that are programmed in PHP and SQL, and relaying their information bidirectionally over wired and wireless electromagnetic signals to billions of small digital computers across the planet. Since the invention of the Printing Press, I am not sure that our species has made such an important contribution toward free, free information. Nimur (talk) 14:51, 30 December 2010 (UTC)[reply]
Nimur, thank you for bringing attention to the lack of flashing lightbulbs that blink on Wikipedia. Hopefully this will help the problem a bit: Bkell (talk) 15:01, 30 December 2010 (UTC)[reply]
Do you think you could design a wikipedia-bot to make those blink every time vandalism is added to the project? Just monitor the recent-changes RSS feed and filter by evil bit. Nimur (talk) 15:31, 30 December 2010 (UTC) [reply]
Timeline of historic inventions (permanent link here) has inventions from the 21st century.
Wavelength (talk) 15:55, 30 December 2010 (UTC)[reply]
Some other inventions in the "change your life" category might be GPS, Virtual Reality, flat screen (and now 3D) TVs, etc. While not all of these technologies are yet fully implemented, at some point we may instantly always know where we are relative to our destination (thanks to GPS) and be able to do many activities (games, shopping, exercise, gatherings with friends & family, business meetings, etc.) without leaving our living rooms (thanks to VR and high tech TVs). StuRat (talk) 18:07, 30 December 2010 (UTC)[reply]
It seems a little counter-productive that half our inventions are about finding your way around outside easier and the other half are designed to keep you from wanting to leave your house. Matt Deres (talk) 19:35, 30 December 2010 (UTC)[reply]
Well, they both seem designed to keep us from getting lost outside. It would have made for a different ending to The Shining, although perhaps Jack never would have gone nuts in the first place, if he had a Wii to play with, instead of talking with ghosts. :-) StuRat (talk) 20:08, 30 December 2010 (UTC)[reply]
Should someone come up with a cheap flying car, I would be first in line to vote to have its use heavily restricted. It's bad enough dealing with the hazards of regular automobiles, even though we've had hundreds of years to develop rules, regulations, and infrastructure to support them. The last thing I want is everyone and everybody flying a plane over my house! --Mr.98 (talk) 18:12, 30 December 2010 (UTC)[reply]
Here are some answers to specific inventions you asked about:
Flying car ? These have been made, but aren't very practical. Cars need to be tough, which means heavy, since we want to be able to survive a fender-bender, and they can't have big wings on them. The wings can be removed, but then must be stored somewhere, which is almost as inconvenient as just storing a whole plane. Thus, this may never be practical.
My automatic driving car ? This is a possibility, and work is being done on this now. The problem is safety, as a car that crashes only 1/1000th of the time would still be completely unacceptable. In the meantime, we could maybe have a car supplement your own driving, like warning you of hazards and pulling off the road and bringing the car to a safe stop if you slump over the wheel.
My maid robot ? This is probably the most practical invention in the short run. If it's small and light enough, and doesn't have sharp parts, it shouldn't be particularly dangerous, so we could handle ones that make occasional mistakes. They likely will be given one task at a time, until eventually they do most of the things a maid would do. We have vacuuming handled by the Roomba, and there are others that can deliver drinks, control the lights and temperature of a house, order food from the grocery store, etc. Whether it's best to leave all these as separate devices or combine them into one is an open question. A big improvement in artificial intelligence is needed to allow for a general purpose robot that you can tell to do something new, like "kill that hairy spider in the tub", so it can figure out all the steps to do it. StuRat (talk) 20:49, 30 December 2010 (UTC)[reply]
Regarding the car, I ask myself if it would crash very often in a specially adapted route. Imagine that you put some sort of sign for the robo-car to orient itself. In a road, it might be easier, mostly, you get a straight line, if something is in front of you, you brake. Quest09 (talk) 21:11, 30 December 2010 (UTC)[reply]
Well, that much is already being done. Cars in the higher price range have systems that, if the car strays too close to the middle line in the road (and the sideline, where applicable), will start shaking the steering wheel and even adjust the course - this is to (to an extent) prevent people from dozing off at the wheel and crashing. And while navigation systems are a far cry from autopilot for cars, you could argue that to an extent they do perform that role - the driver still has to do the actual driving, but now the car or a mounted device in the car takes care of the directions. TomorrowTime (talk) 21:32, 30 December 2010 (UTC)[reply]
The automatic driving car is already reality, it will just need 10 years of technological development and legislation to make it production ready. Both BMW and Audi have demonstrated it. BMW's autonomous 330i did a full-on flying lap of the Top Gear test track (with an extremely frightened Jeremy Clarkson at the wheel just in case he needed to take over the controls). Audi's autonomous TTS did a hill climb at Pike's Peak at a very respectable average speed. The technology is already there: military grade GPS, radar guided cruise control, lane detection systems, automatic road sign recognition, pedestrian and animal recognition, autonomous parking. All it needs is a standardised car-to-car communication protocol (which the manufacturers are already working on). The technology is basically ready, all we need is for it to mature and also for legislation to catch up. Zunaid 08:38, 31 December 2010 (UTC)[reply]
Is there any way of predicting the next killer application like Facebook? If anyone could do that, then their fortune is made. 92.24.176.169 (talk) 19:20, 31 December 2010 (UTC)[reply]
Don't forget Roxxxy. ~AH1(TCU) 17:27, 1 January 2011 (UTC)[reply]
You should know by now that we would have an article on the flying car: Terrafugia Transition. SmartSE (talk) 23:22, 2 January 2011 (UTC)[reply]

Dry cleaning chemical

We use the chemical called Tetrachloroethylene for dry cleaning . However, this chemical has become very expensive due to its increasing scarcity.Kindly recommend either a more easily available and safe to use alternative chemical or a combination of chemicals with their respective proportions. —Preceding unsigned comment added by 41.205.179.120 (talk) 14:12, 30 December 2010 (UTC)[reply]

Dry_cleaning#Solvents_used has some ideas. --Jayron32 14:48, 30 December 2010 (UTC)[reply]

Measuring my PC's power consumption with an oscilloscope

How could I do it? I'd appreciate if someone provided an "equivalent circuit", so that the setup is easier to understand. --Belchman (talk) 22:33, 30 December 2010 (UTC)[reply]

Apologies for not answering your question, but why not use a Wattmeter#Electronic_wattmeter? Are integrating oscilloscopes common? Dbfirs 22:44, 30 December 2010 (UTC)[reply]
You put a low-resistance precision resistor in series with the power flow, then measure the voltage (drop) across the resistor, for example http://www.rcgroups.com/forums/showthread.php?t=393591 You can also build a Current transformer which magnetically couples with the source to provide a fraction of the original current. Ariel. (talk) 22:56, 30 December 2010 (UTC)[reply]
If I understand correctly, by measuring the voltage drop across the low-resistance precision resistor I'll get the current drawn by my PC, right? But what about the voltage? How would I measure it? I'm afraid I can't connect my oscilloscope directly into the mains without getting something burnt. --Belchman (talk) 23:21, 30 December 2010 (UTC)[reply]
I think you can just assume the voltage is correct for where you live (110, 115, 120, 210, 220, etc.). If you want, you can measure voltage separately by running it through a very very high resistance precision resistor, then measuring through (NOT across) that resistor. It's A/C though, so the voltage is a bit complicated. If you are willing to assume it's a sine wave, then you can filter it slightly and then apply a correction factor (I don't remember how much). You'll need to do the same correction for the current as well since it's A/C current. Or you can leave it unfiltered and watch the waveform as is (see power factor to learn a bit more about what it will look like). Ariel. (talk) 23:39, 30 December 2010 (UTC)[reply]
This may sound really dumb, but what's the difference between "measuring through" and "across" the resistor? Probably I'm more than familiar with the concept, it's just the wording (I'm not a native speaker of AmE). --Belchman (talk) 23:52, 30 December 2010 (UTC)[reply]
Through:
----/\/\/\/\/\/\/\----(measure)-----

Across:
----/\/\/\/\/\/\/\------
    |             |
    |             |
    \--(measure)--/

Ariel. (talk) 00:13, 31 December 2010 (UTC)[reply]

Okay, that's what I thought. Anyway, it's a bit weird to my understanding to be measuring voltage "through" since there's no such thing as "absolute" voltage. I guess the "through" measure is the voltage between that point in your chart and the ground, right? --Belchman (talk) 00:31, 31 December 2010 (UTC)[reply]
In my chart the voltage source and sink is on the left and right (the open lines). When I say "through" it means the voltage passes through the resistor before being measured. Ariel. (talk) 01:25, 31 December 2010 (UTC)[reply]
BTW, I'm answering because you asked. But I'm a bit worried about you building/measuring this without really understanding it. At the very minimum please run all your tests via a GFCI outlet. Ariel. (talk) 23:41, 30 December 2010 (UTC)[reply]
(After Edit Conflict)
I'm not sure than an oscilloscope is the right tool for this job. Scopes are very versatile, so I'm sure some clever person could devise some way of making it work with enough extra components, but wouldn't you be happier with a watt meter like a Kill A Watt? APL (talk) 23:42, 30 December 2010 (UTC)[reply]
I'm an electrical engineering student and I have this cheap oscilloscope. I'm just 'playing' with it a little in order to understand it better. --Belchman (talk) 23:46, 30 December 2010 (UTC)[reply]
"Playing" with mains electricity isn't to be recommended... perhaps you should wait until you are further on in your studies when you'll be able to answer questions like this yourself. Then you should be able to experiment in a safe manner. --Tango (talk) 23:56, 30 December 2010 (UTC)[reply]
I should have said that I'm a graduate student, not an undergrad. And believe me it's surprisingly difficult to gather information about such a simple thing like this one... --Belchman (talk) 00:07, 31 December 2010 (UTC)[reply]
The reason you're finding it hard is that an oscilloscope is not the usual tool for the job. Most people who want to measure power consumption do it either directly with a wattmeter or indirectly with a voltmeter. --Carnildo (talk) 01:03, 31 December 2010 (UTC)[reply]
I strongly recommend that you do not attempt any of the suggestions above. Measuring directly at the mains cables is only something to be done if you are sure you know exactly what you are doing. I am fairly convinced that not even the people making the suggestions know what they are doing here. For instance, no one has mentioned that the scope needs to be earth free if the measurement is not to end with a loud bang and tripped breakers. Taking the earth off equipment is something that is done in a controlled lab environment but is in no way suitable for use in a home - especially one with children and pets present. In short - don't do it. SpinningSpark 16:32, 31 December 2010 (UTC)[reply]

If your house has an mechanical electric power meter with a spinning disk then you need only a stopwatch to calculate the power consumption of your PC, see Electricity meter#Electromechanical meters. Cuddlyable3 (talk) 00:59, 31 December 2010 (UTC)[reply]

Not a bad idea. Years ago I had one of these mounted above my workbench, with one side set to plug into the wall, and another with a socket for the device under test. Worked fine, though it was a little slow. No idea how to get one, and no memory of how I got mine. PhGustaf (talk) 01:11, 31 December 2010 (UTC)[reply]

Belchman, why do you think that you, "can't connect my oscilloscope directly into the mains without getting something burnt"? What is the voltage range of your 'scope? Do you have a 10:1 probe? If not, do you know the input impedance of your 'scope, and using that information, can you construct one using some appropriate resistors? Earlier replies told you how to measure the current waveform, so that, with a measurement of voltage, will give your the volt-amps. Are you satisfied with the apparent power or do you want to know the real power dissipated by you appliance? Is your 'scope dual channel, allowing you to measure the phase difference between the current and voltage? -- 119.31.126.66 (talk) 01:56, 31 December 2010 (UTC)[reply]

The current drawn by a PC is far from sinusoidal so a simple phase comparison with the supply voltage is not possible. One would need to measure the voltageXcurrent products at many points on the waveform and integrate. This would be practical only on a dual-channel digital recording oscilloscope. Cuddlyable3 (talk) 03:03, 31 December 2010 (UTC)[reply]
We are not allowed to give medical or legal advice, but dangerous electrical advice is perfectly ok? Apparently. I suggest that the OP buys something like this. Cheaper than an oscilloscope and perfectly safe to use. SpinningSpark 15:57, 31 December 2010 (UTC)[reply]
Here's another one SpinningSpark 16:00, 31 December 2010 (UTC) Marked "Out of stock. Discontinued." Cuddlyable3 (talk) 20:42, 1 January 2011 (UTC) [reply]
Surely a graduate electric engineering student, as you say you are Belchman, would know how to do all this already? Including how to measure through or across a resistor. Unless American degrees are like British A-levels. 92.24.185.225 (talk) 12:35, 2 January 2011 (UTC)[reply]

Elevated temperatures makes Molybdenum react with oxygen to make tetraoxide. What is the threashold, in other words, which is the temperature point that makes Molybdenum form Molybdenum Tetraoxide with certainty?199.126.224.245 (talk) 23:51, 30 December 2010 (UTC)[reply]

No, the article says that it forms molybdenum trioxide with oxygen at high temperatures. The molybdenum trioxide article also gives values for standard enthalpy of formation and standard entropy. If you could locate a value for standard free energy of formation, you could get a fairly close answer to your question using the equation ΔG = ΔH - T * ΔS, where ΔG is free energy, ΔH is enthalpy, ΔS is entropy, and T is the temperature you are looking for. --Jayron32 00:53, 31 December 2010 (UTC)[reply]
Here. Will update the article shortly (you certainly mean trioxide - tetraoxide is not known). Materialscientist (talk) 02:07, 31 December 2010 (UTC)[reply]
It says molybdenum suffers from catastrophic oxidation above 790°C.--Stone (talk) 08:39, 31 December 2010 (UTC)[reply]
There is a problem with the question. Molybdenum trioxide becomes less stable with increasing temperature, not more stable. The same is true for any metal oxide. If you solve for ΔG = 0 (equilibrium), then ΔH = TΔS at T = 2208 K for MoO3 ⇌ MoO2 + ½O2. But the reaction of oxygen with molybdenum is slow at room temperature, not least because you get a protective oxide layer on the metal surface. If you heat the molybdenum in air, the oxidation becomes faster, especially above 795 °C when the layer of MoO3 on the metal surface melts. Physchim62 (talk) 11:32, 31 December 2010 (UTC)[reply]

December 31

A question that is about 15 years overdue: What'll it take for beanies to actually fly the wearer?

In my childhood, I remembered reading a lot of Calvin & Hobbes humor comics. Calvin waited 6 weeks for a Beanie to arrive in his mail, after ordering it through a magazine catalog (IIRC.)

While he waited, he dreamed of flying all through the sky with the beanie, while holding it by the handles.

Then one day, it arrived. He put it together and got it to run. However, the motor wasn't giving it enough of a spin to lift him off the ground. Calvin got enraged, smashed it up, and vented to his tiger pal Hobbes about it.

I had wondered what it would take to make a beanie that actually flies the wearer, but back in the mid '90s, there was no Wikipedia (and its Reference Desk), no Answerbag, no AOL Answers, nor any other Q&A sites I was aware of back in the days of crawling through the "Information Superhighway" on 14.4k modems.

(On what online venue could I have asked this question back in '95-'96 anyway?)

Now, what would need to be invented in order for a beanie to actually fly the wearer, and safely? --66.139.120.57 (talk) 02:03, 31 December 2010 (UTC)[reply]

For one, bigger blades; I am not sure the standard propeller blades on a beanie could generate enough Lift to actually pick you up off the ground. You'd also need a motor to drive the blades. Furthermore, helocopter blades will tend to twist you out of alignment; so you'd need a counteracting set of blades; either a second set which rotated in the opposite direction, like the this one or a second blade at right angles to the main ones, like the this one. --Jayron32 02:25, 31 December 2010 (UTC)[reply]
Or Coaxial rotors. Ariel. (talk) 03:04, 31 December 2010 (UTC)[reply]

This question is 3 months premature. Cuddlyable3 (talk) 03:17, 31 December 2010 (UTC)[reply]

How so? WikiDao(talk) 05:08, 31 December 2010 (UTC)[reply]
20110401. Cuddlyable3 (talk) 20:22, 1 January 2011 (UTC)[reply]
Lol. :) WikiDao 04:35, 2 January 2011 (UTC)[reply]
Incredible hair grips (bobby pins). Bielle (talk) 03:20, 31 December 2010 (UTC)[reply]
And strong neck muscles! - 220.101 talk\Contribs 05:21, 31 December 2010 (UTC)[reply]
You would find that after you added all the things needed to make this practical, it would be a helicopter. StuRat (talk) 08:50, 31 December 2010 (UTC)[reply]
But a smaller one. My guess based on some googling is that you need approximately 8 foot blades to lift a human. There are some website that give formulas to calculate the lift of a helicopter. You can't increase the lift forever - once you hit the speed of sound you can't do any better. At lower altitudes you can use smaller blades because the air is thicker, so you need to take into account how high you plan to go. Ariel. (talk) 09:18, 31 December 2010 (UTC)[reply]
It's already been done! Here's an example of a personal propeller beanie. Well, sort of. It looks dangerous as hell, and has definite shades of Inspector Gadget. Eyeballing the video, I'd say it has a pair of (roughly) four-foot diameter counterrotating blades. Here's another slightly larger and probably slightly safer model. See also backpack helicopter, for which we have an article. TenOfAllTrades(talk) 15:23, 31 December 2010 (UTC)[reply]
I never knew that was actually possible in the laws of physics. Of course, it's got support and a seat for the rider. Looking at the actual C&H strips, you can see it's just a hat with a propeller.
But man, I agree that it looks dangerous as hell...scary! Crimsonraptor | (Contact me) Dumpster dive if you must 22:20, 31 December 2010 (UTC)[reply]

Effects of drunkenness on physical ability

My local news just showed a video of a suspected DUI traffic stop in which the driver failed in his attempt to walk a straight line — however, after stumbling and giving up, he proceeded to turn a cartwheel. How is it that alcohol can prevent someone from walking straight but not from maintaining the balance and agility necessary to avoid falling over like I do when I try to turn a cartwheel while sober? Nyttend (talk) 04:09, 31 December 2010 (UTC)[reply]

The issue is that DUI tests are standardized; they need to be to be admissable as evidence in a court of law. Officers perform the same set of standardized tests, and videotape the evidence. Turning cartwheels isn't a part of the standardized set of DUI tests in any state I know of. So the fact that one could do so doesn't make any difference in establishing reasonable suspicion to arrest someone for DUI. If litigated in court, I suppose that the defendent could perhaps use such cartwheel as evidence that he was sober enough to drive; but that wouldn't mean that the officer at the scene would be wrong for arresting the person for DUI if they failed the standardized tests. They may argue to get their license back based on that evidence, but that has no bearing on how the arresting officer should act at the scene. The officer should always do it "by the book": administer the standard tests, and if the standard tests are failed, place them under arrest. Let the courts deal with anything that comes later. --Jayron32 04:24, 31 December 2010 (UTC)[reply]
I wasn't trying to question the claim that he was drunk; the rest of his behavior made it obvious that he was very much under the influence. My question asked how he could perform a cartwheel despite being unable to do much simpler things. Nyttend (talk) 05:04, 31 December 2010 (UTC)[reply]
Ah. Yes. My bad. Sorry. --Jayron32 05:07, 31 December 2010 (UTC)[reply]
Balance depends heavily on feedback-driven control, which is particularly impaired by alcohol. A cartwheel is a complex motor sequence, but it doesn't depend very heavily on feedback. Looie496 (talk) 04:59, 31 December 2010 (UTC)[reply]
Can you explain what you mean by "feedback"? I've read the "Biology" section of our feedback article; its final paragraph somewhat resembles what I think you mean, but it seems somewhat irrelevant, so I suspect that you mean something different. Nyttend (talk) 05:08, 31 December 2010 (UTC)[reply]
In order to balance, your body needs to get information about where it is now and use that information to maintain that position. So your brain analyzes a whole shitload of information; some from your inner ear, some from the tension on your muscles, some from your vision, to determine where you are in relation to, say, the ground, and then based on that information, it makes minute adjustments to your muscles to keep you standing straight and balanced. Alcohol short-circuits that feedback, so while you may be fully in control of your muscles while drunk, your brain is receiving bad information about your "location" in the world, so it cannot easily autocorrect if you are falling. That's why drunks fall over; not because they don't have muscular control, but rather because their automatic balancing system is receiving fuzzy information. --Jayron32 05:15, 31 December 2010 (UTC)[reply]
... and safe driving relies on this "feedback", so the walk test is better than the cartwheel test. Even drunk drivers can make a car cartwheel! Dbfirs 10:16, 31 December 2010 (UTC)[reply]
... and turning a cartwheel cannot be performed by anyone able to drive, so it has no value as a test, since a DUI test should be positive for all (or most) drunk drivers and negative for all (or most) non-drunk drivers. However, why put people to walk? In Europe, as far as a I know, they always use a breathalyzer. If you want, you can request an additional, more precise blood testing. Quest09 (talk) 20:51, 31 December 2010 (UTC)[reply]
Not to say any of the above comments are wrong, but to answer the question a bit more directly, the "biology" part of the feedback article doesn't really cover its role in motor control -- the "control theory" section is more relevant. Basically feedback control of a movement means noting errors in the execution and adjusting the movement to reduce them; feedforward control means generating the correct muscle activity before any useful feedback comes in. In a cartwheel, by the time you have noticed that you screwed up, it is too late to do anything about it. (The feedback is however useful for learning -- if you get something wrong, you can try to change it on the next attempt.) Looie496 (talk) 23:47, 31 December 2010 (UTC)[reply]

How can the universe be infinite?

The article Universe says that "The universe is very large and possibly infinite in volume.". However, this seems at odds with logical thinking.

  • The universe is expanding at a very high speed, but not at an infinite speed. Let's call this speed x
  • The universe has been expanding for a very long period of time, but not an infinite period of time. Let's call this time t.

Therefore, the current size of the universe should be a direct function of t and x. If neither x nor t are infinite, how can the size of the universe be infinite at any given moment? Thanks. Leptictidium (mt) 07:43, 31 December 2010 (UTC)[reply]

I'm not a cosmologist, but my general understanding is that if the universe is infinite in extent now, then it always has been. It's often claimed that the big bang means that the universe sprang from a single point, but that is not in fact a necessary part of the theory. If you run the equations backwards you get to a moment when the universe was infinitely dense, but it did not necessarily have zero volume. --Trovatore (talk) 07:55, 31 December 2010 (UTC)[reply]

If the infant universe had infinite volume and infinite density, then it must have had infinite mass (since density is a function of mass and volume). However, our present universe does not have infinite density, so where did all the mass go? Leptictidium (mt) 08:17, 31 December 2010 (UTC)[reply]

If it has infinite volume now, and density finite but bounded away from zero (that is, there is some nonzero density such that every part of the universe is at least that dense), then it also has infinite mass now. So why did it have to go anywhere?
As I say, I'm not coming at this from a very sophisticated angle, but I don't see any insuperable problem here. --Trovatore (talk) 23:07, 31 December 2010 (UTC)[reply]
For one thing, the big bang wasn't necessarily the whole universe, it could have just been a portion, and there may have been many other big bangs, far away. We wouldn't know about these other big bangs unless one of them expands into ours. StuRat (talk) 08:45, 31 December 2010 (UTC)[reply]

That does not answer the question of why we don't have infinite density now if we had it in the past. Leptictidium (mt) 08:54, 31 December 2010 (UTC)[reply]

I recently completed a second year cosmology paper, and what I was told is that the universe is not infinite, neither does it have an edge. The best definition of the edge of the universe you can get is halfway between the centre of the universe and itself. In other words, if you had a ridiculously long pole, growing longer at the same rate as which the universe is expanding, you should be able to tap yourself on the shoulder. --Plasmic Physics (talk) 09:10, 31 December 2010 (UTC)[reply]
Could you please post a link to a resource which deals with this theory in more detail? Thank you. Leptictidium (mt) 09:30, 31 December 2010 (UTC)[reply]
Well, you can write down models where space is finite in total area without "ending" anywhere. The surface of the Earth is also like that. There's no central point on the surface of the Earth, and any point on the surface could be described as "halfway between the antipodal point and itself", though it's probably better not to describe it that way. There's no evidence favoring those models over other models, but they are at least consistent with the available evidence. -- BenRG (talk) 10:32, 31 December 2010 (UTC)[reply]
What cosmologists mean by the "total size of the universe" and the "expansion of the universe" doesn't exactly match the everyday meaning of the words, in part because in general relativity the distinction between space and time is a bit fuzzy. Shown to the right is the Milne universe, which is basically a simplified (numerically inaccurate) version of standard cosmology that's easier to visualize in a 2D diagram. This model is spatially infinite at all times, in the sense meant by cosmologists. See the previous Ref Desk threads Light from just after the Big Bang and Infinite amount of mass in the universe? where I mention the Milne model, and Speed in space which has a more accurate picture. And also see Ned Wright's cosmology tutorial. -- BenRG (talk) 10:32, 31 December 2010 (UTC)[reply]
@Leptictidium: You asked why we have finite density now if we had infinite density in the past. It is important to realise that this question is actually the wrong way round (no blame - I make that kind of mistake too often myself). We do not know that the density was infinite in the past; what we do know is that now it is finite. The "correct" question would then be why we had infinite density in the past when we have finite density now, and we can answer that one. We also know that the universe is expanding (i.e. mean density is decreasing) and we have a theory for that expansion. Using that theory and our knowledge about the present state of the universe as initial condition, we can determine how the mean density of the universe evolved in the past. Doing that we find that the density increased (going backwards in time) without bound. The point where the density formally diverges (becomes infinite) is called the "Big Bang". The Big Bang is just that: an extrapolation backwards in time. However, we also know that our theory breaks down at some point when the mean density becomes larger than what we can handle with our knowledge of quantum theory and general relativity. Hence, the big bang is a simple extrapolation beyond our secure knowledge of physics. Unfortunately, the big bang is, especially in popular science books and documentaries, often represented as a secure fact and it is way overstressed. The initial question, whether the universe is finite or infinite, is not answered yet. We do have some constraints on the minimum possible size (if it is finite), nothing more. There is a nice book about this topic (the topology of the universe) by Jean-Pierre Luminet, which is available in English, I think. --Wrongfilter (talk) 11:45, 31 December 2010 (UTC)[reply]
The way I see it, if the universe were expanding at the speed of light in all directions, and we are correct that it is impossible to exceed the speed of light, then for all intents and purposes, the universe would be infinite since you can never get to any edge. Googlemeister (talk) 15:07, 31 December 2010 (UTC)[reply]
The universe is not expanding at the speed of light. The rate of increase of distances (which is not a velocity!) is proportional to the distance (suitably defined) and is not limited by the speed of light. --Wrongfilter (talk) 15:35, 31 December 2010 (UTC)[reply]
Matter cannot travel faster than the speed of light, but metric expansion of space itself can, and any two objects travelling apart faster than light speed will be beyond the edge of the other object's respective visible universe. See also dark energy and shape of the universe. ~AH1(TCU) 17:23, 1 January 2011 (UTC)[reply]
The connection with the visible universe is not correct. The rate of increase of the distance between two objects (they are not "travelling" - where would they travel to?) is equal to 300000 km/s (the speed of light) when they are at a distance of 4.28 Gpc (for H0=70 km/s/Mpc), that corresponds to a redshift of 1.45 (per Ned Wright's cosmology calculator), nowhere near the horizon. The speed of light has nothing to do with the metric expansion of space. --Wrongfilter (talk) 18:03, 1 January 2011 (UTC)[reply]
Expanding on Wrongfilter's reply: in the Milne universe, shown above, there's no upper limit to the cosmological recession speeds, even though the special relativistic speeds of the very same objects are all less than c. The cosmological recession speed in this case is equivalent to rapidity (times c, since rapidity is usually given as a unitless number). A rapidity of 1 (or c) has no special significance. It's like an angle of 1 radian. -- BenRG (talk) 01:31, 2 January 2011 (UTC)[reply]

If I evaporated a solution of antimony trichloride in a solution of concentrated hydrochloric acid, would the antimony trichloride precipitate as a solid? --Chemicalinterest (talk) 12:47, 31 December 2010 (UTC)[reply]

Most of the chlorides if produced by this way would give the oxide and hydrochloric acid. I have to have a look for the example of antimony trichloride, but I doubt that the compound is stable in water at all.--Stone (talk) 13:34, 31 December 2010 (UTC)[reply]
The group 15 elements form a huge range of oxohalides as well. SbOCl is the simplest example in this system, but there are many others. Also, SbCl3 is described as deliquescent, so you are not going to be able to form a solid by evaporation at ambient temperature and pressure. Raising the temperature or lowering the pressure will drive off HCl before it drives off water, and so promote hydrolysis of the chloride to the oxochloride. In short, no. Physchim62 (talk) 16:05, 31 December 2010 (UTC)[reply]
Sorry! I have to correct myself. Butter of Antimony [3] is the very old name of the compound. Best produced by dissolving antimonsulfid in conc. hydrochloric acid. When always an excess of hydrochloric acid is present the liquid can be evaporated. You get a white substance of waxy consistence ( therefore called Butter of Antimony). If the solution of Antimony trichloride in water is diluted in water a complicated mixture of oxides is formed which at the end will be antimony oxide.--Stone (talk) 17:16, 31 December 2010 (UTC)[reply]

Best length of radio aerial

I have a small mains-powered transistor radio, which had an aerial wire sticking out of the end. The aerial wire has now broken off and I will need to re-attach it, or bin it. The wire was 970mm long. I mostly use it to listen to a radio channel on about 94Mhz, FM. Where I am, reception is not very good. What would be the best length for the new wire aerial? If 970mm was the best length, would there be any advantage in having the wire a multiple of this length, such as twice, thrice, four times, etc? A particular problem I have is that another more intense signal is right next on the dial to what I want to listen to. I still get some reception without the wire attached, but it is not as good. Please do not suggest buying a DAB radio as the signal is not good enough here, regretably. Thanks 92.24.176.169 (talk) 19:45, 31 December 2010 (UTC)[reply]

Under ideal conditions the best length, a quarter wavelength with some adjustment for end effects, would be about 760 mm. It sounds like your biggest problem is the stronger station, and a longer wire would just make the strong station stronger. If the weak station and the strong station are in different directions, try putting some kind of metal screen in the direction of the strong station. Jc3s5h (talk) 20:00, 31 December 2010 (UTC)[reply]
Ignoring the nearby radio channel, would multiples of 760mm be better? Would odd- or even-multiples be preferred at all? 92.24.176.169 (talk) 20:41, 31 December 2010 (UTC)[reply]

I've seen the article Random wire antenna, and apparantly half-wavelength aerials are to be avoided. I don't mind having a very long wire: what length would be best? 92.24.176.169 (talk) 21:19, 31 December 2010 (UTC)[reply]

  • Odd multiples will match the impedance of the input stage better, an even multiple will have a high impedance. However boosting the input will overload the radio more and increaase the problem due to the interfering station. If you have the space a dipole antenna connected via a balun to the antenna input will get you more control. Match the polarization and rotate to minimise the interfering station. Graeme Bartlett (talk) 22:08, 31 December 2010 (UTC)[reply]

The aerial has only one connection, I would not know where to connect the other half of a dipole. From what I remember of other radios, dipole antennas for VHF are not very big. If the interfereing channel is ignored, would for example a 3/4 wavelength monopole be better than a 1/4 wavelengtn monopole? 92.24.185.151 (talk) 23:23, 31 December 2010 (UTC)[reply]

The aerial has only one connection... That is what you need the balun for, it converts balanced (dipole) to unbalanced (aerial socket plus chassis). SpinningSpark 23:42, 31 December 2010 (UTC)[reply]
On the length question, there is no advantage in using 3/4λ instead of 1/4λ. To get any advantage over a dipole you would need to use something more complicated, such as a Yagi antenna. SpinningSpark 23:49, 31 December 2010 (UTC)[reply]
Huh? A Yagi aerial is a variety of dipole aerial. 92.15.14.57 (talk) 15:03, 1 January 2011 (UTC)[reply]
Uhuh. A Yagi aerial enhances the directionality and gain of a dipole aerial. Cuddlyable3 (talk) 20:14, 1 January 2011 (UTC)[reply]

Please explain why a 1/4 wavelength aeriel will be better than an aerial three times as long as this, I'm sceptical. The longer aeriel will collect three times the signal energy. (And three times the signal energy is nothing compared to the higher signal intensity of someone living nearer the transmitter, so the radio should be easily able to cope with it). The Wikipedia antenna article also says: "The random wire antenna is simply a very long (at least one quarter wavelength) wire with one end connected to the radio and the other in free space, arranged in any way most convenient for the space available. Folding will reduce effectiveness and make theoretical analysis extremely difficult. (The added length helps more than the folding typically hurts.)". That says nothing about a quarter walevlength being best, and the links I've read also say nothing about a quarter wavelength being best, although warning against using a half-wavelength or multiples of that. 92.15.14.57 (talk) 14:46, 1 January 2011 (UTC)[reply]

The thing about a random wire antenna is for cases where a 1/4 wavelength is impossible to string - it's just too long. So instead a wire is placed randomly. If you actually can run the wire to the correct length then do that. Ariel. (talk) 23:50, 1 January 2011 (UTC)[reply]
But you have still not explained why 1/4 wavelength is better (if it is) than a larger 3/4 wavelenth aerial. 92.24.185.225 (talk) 12:20, 2 January 2011 (UTC)[reply]
You may also be interested in our fractal antenna article. WikiDao 04:43, 2 January 2011 (UTC)[reply]

Oooh, perhaps I should just buy a fractal aerial from somewhere like Maplin or even cut one myself from cooking foil. Edit: Maplin do not have any fractal aerials. 92.24.185.225 (talk) 12:20, 2 January 2011 (UTC)[reply]

I'm getting a little weary of your sarcasm and argumetativeness. Volunteers have answered your questions with detailed and accurate answers. Please show some politeness to them, even if you don't like the answers. If you would rather follow your own advice, that is ok with us too. SpinningSpark 14:21, 2 January 2011 (UTC)[reply]

January 1

When beer is left in an open container for a long time

What besides alcohol evaporates? I don't hold drinks well so while it doesn't taste good I wonder if it's better for me. Imagine Reason (talk) 00:21, 1 January 2011 (UTC)[reply]

Well, the carbonation will be lost, and the water in the beer will begin to evaporate as well. I doubt it would be any better for you to drink flat warm beer. Beeblebrox (talk) 00:26, 1 January 2011 (UTC)[reply]
Carbonation is bad for your teeth, in that it forms carbonic acid, which can etch the surface and allow cavities to form. So, in a sense, flat beer is healthier. StuRat (talk) 06:22, 1 January 2011 (UTC)[reply]
(ec) I don't think it loses much alcohol in moderate time, because there isn't that much to start with. (Whiskey, on the other hand, becomes substantially weaker in a few hours, I think.)
What beer mainly loses when left open is carbon dioxide, which gives it its fizz. Most people don't like "flat" beer. --Trovatore (talk) 00:27, 1 January 2011 (UTC)[reply]
(ec)Not sure what you mean by "better for you". You may be better off with a Soft_drink if you don't like beer, especially if you're driving. What happens to beer depends how long it's left. After a few hours the carbonation will go, as Beeblebrox says. The beer will also warm up to room temperature. Some beers taste better very cold, and are traditionally drunk in this state (US and Australian beers in particular) while others, such as UK "bitter" are more often drunk at room temperature. So some beer will taste nasty, other beer won't. After a few days in an open vessel the sugars in beer will start to grow mould and the sugars will turn to vinegar. How long do you mean by a "long time"? Tonywalton Talk 00:40, 1 January 2011 (UTC)[reply]
Agree that before much alcohol has evaporated the quality will be affected. By the way, English bitter should be drunk at cellar temperature, i.e. about 9degC. It isn't heavily carbonated like canned beer. Itsmejudith (talk) 17:07, 1 January 2011 (UTC)[reply]
How about trying low/no-alcohol beer? 86.185.77.168 (talk) 02:52, 2 January 2011 (UTC).[reply]

White precipitate

When tin is reacted with copper sulfate, a white precipitate is formed. What is this? --Chemicalinterest (talk) 01:30, 1 January 2011 (UTC)[reply]

Tin(II) sulfate would be my best guess. --Jayron32 02:55, 1 January 2011 (UTC)[reply]
Strange, the fact that you didn't observe a red or dark orange precipitate, means that copper(2+) was not reduced to copper(0). --Plasmic Physics (talk) 08:56, 1 January 2011 (UTC)[reply]
Tin(II) sulfate is soluble and, I would presume, is in the (almost) colorless solution above the white precipitate. --Chemicalinterest (talk) 12:36, 1 January 2011 (UTC)[reply]
Maybe Tin(IV) sulfate then? I can't see anything happening to the sulfate itself, and copper compounds are all usually brightly colored. --Jayron32 15:30, 1 January 2011 (UTC)[reply]
Depending on the pH, you might have hydrated tin(II) oxide. Physchim62 (talk) 16:27, 1 January 2011 (UTC)[reply]
It is only as acidic as a dilute solution of copper sulfate is. --Chemicalinterest (talk) 18:11, 1 January 2011 (UTC)[reply]
Which may actually be pretty acidic; copper(ii) is a pretty decent lewis acid, and in solution readily forms copper hydroxide complexes, leaving hydronium behind. --Jayron32 18:27, 1 January 2011 (UTC)[reply]

I have just completed some tests on a mixture of the almost colorless solution and the white precipitate. Excess HCl dissolves it to form a light yellow-green solution; dilute hydrogen peroxide has no effect on it; and dilute ammonia solution makes the precipitate somewhat more yellow and precipitates more from the solution part. Hope this helps in some way. --Chemicalinterest (talk) 23:04, 1 January 2011 (UTC)[reply]

Complex/Quadrature Sampling

While reading some web pages on Software Defined Radio, I saw a method to get a high sampling rate by using two ADCs of lesser speed. Contrary to intuition, the two ADCs were operated not 180° out of phase but in quadrature. What is the actual name of this technique, and is there a wikipedia page on it? I'm currently reading an external link from the SDR article, but it seems to talk about QAM modulation techniques rather than sampling techniques. —Preceding unsigned comment added by 59.93.16.208 (talk) 06:12, 1 January 2011 (UTC)[reply]

Depending on the exact arrangement, it might be a phase detector combined with an interpolation algorithm; it might be simply a quadrature sampler; it might be an interferometer (if the Q/I components are compared to a reference signal). There are a wide class of methods that use 90-degree (quadrature) modulation to analyze signals; the exact circuit might help us narrow down the method. Our quadrature article links to some of the numerous uses and applications of 90-degree phase shift for signal analysis; because of the unique properties of fourier analysis, phasing a signal by 90-degrees (in other words, "multiplication of the signal by i) allows additional information to be inserted or extracted from a waveform, because the quadrature signal is orthogonal to the original signal. So many related techniques rely on this quadrature orthogonality property, it's difficult to name a specific one without looking at the exact circuit. Nimur (talk) 08:17, 1 January 2011 (UTC)[reply]
I was reading the GNU Radio site. This is what they have written about the hardware. They have also given an image in which the input from two ADCs are multiplied with Sin and Cos.
The USRP has 4 high-speed analog to digital converters (ADCs), each at 12 bits per sample, 64MSamples/sec. So in principle, we have 4 input and 4 output channels if we use real sampling. However, we can have more flexibility (and bandwidth) if we use complex (IQ) sampling. Then we have to pair them up, so we get 2 complex inputs and 2 complex outputs.
Where would the bandwidth advantage come from? 59.93.6.216 (talk) 17:22, 1 January 2011 (UTC)[reply]

The range of signal frequencies that can be sampled without alias error is said to be limited at half the sampling frequency, called the Nyquist frequency. Alias error here refers to false readings of signal frequencies above the limit. The sketches below demonstrate that phase errors still occur at the Nyquist limit. In the upper sketch the solid samples are at the Nyquist rate and appear to allow an unambiguous reconstruction of the sinewave signal. However with an unfortunate sampling phase relative to the signal, we get the open samples which are all zero. Simply shifting the signal phase by 90 degrees has made it "invisible" to the sampler. In contrast, the lower sketch shows the 0-90-360 degree sampling described by the OP. Here there is no phase ambiguity. Both I and Q (quadrature) components of the signal can be reconstructed. What has been obtained is not an increase in bandwidth but a removal of (amplitudeXphase) ambiguity.

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Cuddlyable3 (talk) 20:04, 1 January 2011 (UTC)[reply]

Black hole

I have read somewhere that if a fragment of a red giant remains during the explosion, the star collaspes into a black hole. Is this true? Also what causes the super giant to become a black hole and not a Neutron star? What's the deciding factor between these? --Tyw7  (☎ Contact me! • Contributions)   Changing the world one edit at a time! 08:10, 1 January 2011 (UTC)[reply]

The final stage of stellar evolution is either a white dwarf, neutron star or black hole in order of increasing mass; and it is the mass which entirely determines which it is to be. SpinningSpark 10:13, 1 January 2011 (UTC)[reply]
Also, I think you are confused between red giants, which do not explode and is something that happens to smaller/mid-range stars and supernovae, which do explode and is something that happens to larger stars. There is always a remnant after such explosions. SpinningSpark 10:20, 1 January 2011 (UTC)[reply]
Red supergiants and blue supergiants are the stars that can either evolve into a neutron star or black hole. Core remnants almost inevitably remain, except for some Wolf-Rayet stars and select Gamma ray bursts. Also read up on Type Ia supernovas, Type Ib supernovas and Type II supernovas, as the deciding limit between neutron stars and black holes is more uncertain than say, the Chandrasekhar limit but hypernovae if they exist likely become black holes and X-ray sources. ~AH1(TCU) 17:20, 1 January 2011 (UTC)[reply]
Slight correction: the supernovae are the explosions. The stars that go supernova are called supergiants. --Tango (talk) 00:44, 2 January 2011 (UTC)[reply]

Sound

How does a flute work? --75.28.52.27 (talk) 17:59, 1 January 2011 (UTC)[reply]

See the Wikipedia article flute. --Jayron32 18:26, 1 January 2011 (UTC)[reply]

This article (http://www.phys.unsw.edu.au/jw/fluteacoustics.html) seems to have what you need ny156uk (talk) 18:27, 1 January 2011 (UTC)[reply]

A flute doesn't work; it plays. [rimshot] Clarityfiend (talk) 03:04, 2 January 2011 (UTC)[reply]

Dumping snow in the sea

From http://www.bbc.co.uk/news/world-europe-12088442:

"Deep snowdrifts have trapped thousands of people in their homes on the Danish island of Bornholm [...] There is so much snow that islanders have started dumping it in the sea - a practice normally forbidden for environmental reasons."

Does anyone have any ideas what these "environmental reasons" could be? Do you think it's just in case the snow is contaminated by oil or something, say from the roads? 86.185.77.168 (talk) 23:00, 1 January 2011 (UTC)[reply]

It looks like Norway had similar problems two winters ago, and when they started dumping the snow into the sea, there were indeed environmental concerns for the reason you stated: contamination from traffic. See this report, for example. ---Sluzzelin talk 23:26, 1 January 2011 (UTC)[reply]

January 2

Manganese(II) oxide color

Green? This does not seem to correspond with the other manganese(II) compounds' colors. --98.221.179.18 (talk) 01:05, 2 January 2011 (UTC)[reply]

It's not unusual for transition metal oxides to be a different colour from other compounds. The long-range ionic structure can give rise to new sets of energy levels, and so different electronic transitions (which are the basis of colour). So copper(II) oxide is not blue, for example. Physchim62 (talk) 01:55, 2 January 2011 (UTC)[reply]
I produced it by reacting manganese(II) sulfate with ammonia and it came out as a very light brown solid that darkened to a yellow-brown solid upon standing. --98.221.179.18 (talk) 02:09, 2 January 2011 (UTC)[reply]

I-joist

arent I-joist s a violation of building code? they are weaker and more prone to water damage than solid wood 2 by 12's — Preceding unsigned comment added by Tommy35750 (talkcontribs) 01:40, 2 January 2011 (UTC)[reply]

Our I-joist article is silent on your question, although it states that as of 2005, approximately 50% of all wood light framed floors were framed using I-joists. So I'm guessing they are complaint with building codes. In some countries. Which country are you concerned with (as if I could not guess). Our article also says "The biggest notable difference compared to dimensional lumber is that the I-joist is designed to carry heavy loads over long distances while using less lumber than a dimensional solid wood joist of a size necessary to do the same task". That seems to suggest they are stronger, not weaker, than solid wood. You might want to point us at any source which supports your prejudices. --Tagishsimon (talk) 01:46, 2 January 2011 (UTC)[reply]

the article lies and should be changed. by definition any engineered wood is weaker than solid. i joists are basically osb which is not very strong at all. in fact i would like to know where i can report these false advertising claims as they are being told by the manufacturers. im in the usa — Preceding unsigned comment added by Tommy35750 (talkcontribs) 02:02, 2 January 2011 (UTC)[reply]

If you could provide a reference or two to confirm your assertion, that would help. Certainly, I cannot agree with the statement "by definition any engineered wood is weaker than solid". By whose definition? And wither plywood, for instance? --Tagishsimon (talk) 02:06, 2 January 2011 (UTC)[reply]

i am a carpenter — Preceding unsigned comment added by Tommy35750 (talkcontribs) 02:08, 2 January 2011 (UTC)[reply]

That's nice for you. Now, about those references. --Tagishsimon (talk) 02:10, 2 January 2011 (UTC)[reply]
Actually I believe that for equivalent weight/size engineered wood is stronger, not weaker. But usually what they do is reduce the weight and size, and keep the strength the same. Ariel. (talk) 02:11, 2 January 2011 (UTC)[reply]

try to punch through 2 inch solid wood and then 2 inch osb or particle wood then tell me which is stronger — Preceding unsigned comment added by Tommy35750 (talkcontribs) 02:18, 2 January 2011 (UTC)[reply]

Using products in ways not specified for the product is not a good test of the product. From the Oriented strand board article, we learn that "it does have a specific axis of strength". Which implies that it is weak in other axes. So punching through board, when it is designed to be used in compression or tension about a certain axis, is a test of nothing at all. Your 2 inch solid wood is, undoubtedly, stronger in some ways than 2 inch OSB. But if that strength is never to be put to use in its application, then it is wasted. OSB's advantage is that it uses the cheapest wood inputs to provide strength where it is required, and not to provide strength where it is not required. As such, it is less expensive and weights less. And it has other advantages over your solid wood, noted in the I-joist article. --Tagishsimon (talk) 02:27, 2 January 2011 (UTC)[reply]

yes it is cheaper. but is is weaker also. in all areas. — Preceding unsigned comment added by Tommy35750 (talkcontribs) 02:29, 2 January 2011 (UTC)[reply]

Actually Tommy, aaah - nevermind :( hydnjo (talk) 02:50, 2 January 2011 (UTC)[reply]
Please see WP:SOURCE to see what we require for "reliable sources". If you cannot provide any, there's no basis for the article to be changed. 90.193.232.239 (talk) 02:52, 2 January 2011 (UTC)[reply]
Weight for weight, an I-joist will be more efficient at load bearing than a solid joist, for the same reasons as an I-beam is more efficient than a solid steel beam. However, it will have a lower safety factor than a solid joist, so any rules of thumb that are used with solid joists will not necessarily apply to an I-joist. In particular, its tolerance to having holes or channels cut through it will be less than for a solid joist. Quality control during manufacturing and installation is also important. To determine whether I-joists meet your local building codes, you would need to consult a structural engineer who is familiar with those codes - that is not something on which Wikipedia editors can advise you. Gandalf61 (talk) 08:52, 2 January 2011 (UTC)[reply]
Some I-beams, sold in Europe, have a light metal web, rather than engineered wood. The manufacturers' and major vendors' websites usually carry data about strength. If building in the UK you would need calculations by a structural engineer, and they would take the manufacturer's data and feed it into a computer algorithm. If I-beams were unsuitable for building they would not be licensed in so many countries. Itsmejudith (talk) 11:38, 2 January 2011 (UTC)[reply]

LASERs for every wave?

Is it theoretically possible to produce a LASER for every wave length? (that means, sound, IR, radio).Quest09 (talk) 11:32, 2 January 2011 (UTC)[reply]

Yes, although the source will have to vary for example, a GASER (Gamma Amplification by Stimulated Emission of Radiation) is of nuclear origin. A SASER is the sound analogue of a LASER. --Plasmic Physics (talk) 11:55, 2 January 2011 (UTC)[reply]
Also maser for microwaves. SpinningSpark 14:25, 2 January 2011 (UTC)[reply]

Secure flying without sexual harassment

Instead of body scanning or of frisking innocent passengers, couldn't we just put the passenger into a cabin, let air flow through it, and analyze the resulting air? If we found traces of suspicious substances, then we could selectively frisk him. It looks less intrusive than the present practice. Quest09 (talk) 11:52, 2 January 2011 (UTC)[reply]

That won't work with surgically implanted bombs inside bones. For all we know, Al Qa'ida could have recruited medical experts and performed surgery on volunteer suicide bombers in improvised hospitals in South Waziristan (note that Al Zawahiri is an experienced surgeon). There could be many hundreds of such suicide bombers who live normal lifes for a decade and then, one day, they all board different planes at around the same times and trigger the explosion using mobile phones. Count Iblis (talk) 13:13, 2 January 2011 (UTC)[reply]
Honestly, I hope you said that ironically, and that no one thinks this is a real threat. Anyway, the present practice of frisking or scanning won't catch them all, however a metal-detector will do the trick, without invading privacy. 83.40.250.126 (talk) 13:28, 2 January 2011 (UTC)[reply]
Well, I hope that the intelligence services have learned from the liquid explosives threat and start to think about how they would commit terror attacks if they were operating under similar constraints as Al Qa'ida and take measures to close such loopholes, instead of reacting to actual plots. There are many more security experts in the World than there are Al Qa'ida members, so this should be a successful strategy. Count Iblis (talk) 13:41, 2 January 2011 (UTC)[reply]
Might be that there are more security experts than terrorists, but the latter have at least some advantages: secrecy and the shear number of targets. Quest09 (talk) 15:00, 2 January 2011 (UTC)[reply]
The current paranoia is entirely whipped up by the security community, who get their kicks (and their considerable salaries) from demonstrating that they have control over normal human beings. They are just as bad as the terrorists – in fact they do more harm to Western countries than Al-Qaeda could ever manage. They shuld be hunted down and put out of any position to do damage, IMHO. Physchim62 (talk) 14:18, 2 January 2011 (UTC)[reply]
The do not do more harm, unless you consider only economical harm. Quest09 (talk) 15:05, 2 January 2011 (UTC)[reply]

Snow as fertiliser ?

Hello, and happy new year. I'm re-reading the Little House in the Prairie books at the moment and I came across a curious occurrence in Chapter 22 of Farmer Boy. I only have the French issue of the book so I can't give an exact quote, but basically what happens is that it's the end of fall, it snows for the first time and in the morning they find six inches or so of snow outside but the soil isn't frozen yet. Almanzo's father is very pleased, he says that snow is "the poor man's fertilizer" and it contains something that will help plants grow if you plough it into the earth. (Poor Royal has to get out in the cold with the horses and plough all the fields for his troubles.) So, is that only country lore or is there a grain of truth in that ? They're located in New York State near the Canadian border (Malone) and the story is set in 1867 so there wouldn't be many industries around sending stuff in the air, would there ? Thank you, have a nice day. 85.169.173.68 (talk) 12:28, 2 January 2011 (UTC)[reply]

There's a suggested explanation at http://www.weathernotebook.org/transcripts/1999/04/26.html —Preceding unsigned comment added by 86.174.166.79 (talk) 12:45, 2 January 2011 (UTC)[reply]

I need a strong argument about throwing away incandescent lights to replace them with CFLs right away.

Someone I know thinks it's wasteful to throw away incandescent bulbs before they're used up, even though I know that it's more wasteful to keep using more energy when the CFLs (or even LED light bulbs) will start saving right away.

Therefore, how do I counter the argument? I once saw that incandescent bulbs were 25¢ each ($1/4-pack) at Wal-Mart, but assume they're 50¢ each.

Assuming 10¢/kWh, how long would a CFL take to save 50¢, thus justify tossing a single incandescent bulb? (How long would an LED take?)

Now, what do you think of my wish to toss out incandescent lights early in order to replace them with the CFL and LED lights? --64.216.111.57 (talk) 12:41, 2 January 2011 (UTC)[reply]

My CFL's take 23W and my incandescents take 100W. These figures may help. --Chemicalinterest (talk) 12:47, 2 January 2011 (UTC)[reply]
And using those numbers, with my electric rate (8.75¢/kWh), I'd save .65¢/hour per CFL used versus an incandescent. At that rate, it takes less than 80 hours of use to come out ahead with 50¢ CFLs. — Lomn 14:25, 2 January 2011 (UTC)[reply]

Can some deaf people hear what they see?

I've read that some blind people can see using their tonge. A camera sends electrical signals to nerves in the tongue and the blind person, over time, starts to see pictures. So, the brain is able to process information from one sense as if it arrived via another sense. Also, in case of hearing, visual information can strongly influence what we hear, as the McGurk effect clearly demonstrates, see also this video to check it out for yourself. It thus seems plausible to me that a lipreading deaf person could actually hear what he/she is lipreading, but I have never read about this. Count Iblis (talk) 13:28, 2 January 2011 (UTC)[reply]

That video is really wierd. If I look at the left image with my left eye and the right image with my right eye, I can hear both words simultaneously. I recently read of an experiment where images were digitally processed and then "projected" on to the subjects stomach via transducers on the skin. This was very low resolution, but apparently the subjects could form the image in their brain after a little practice just as if it had come from their eye rather than their stomach. Sorry, I don't have a link to hand. SpinningSpark 15:05, 2 January 2011 (UTC)[reply]
Not exactly the same thing, but you might be interested this paper also. SpinningSpark 15:28, 2 January 2011 (UTC)[reply]
See this book SpinningSpark 15:40, 2 January 2011 (UTC)[reply]

What are the lines in this picture?

I'm presuming warning flares fired prior to the explosion itself? Or part of the testing process? Bobby P Chambers (talk) 15:10, 2 January 2011 (UTC)[reply]

According to this site, "The lines that you see in this and several other photos are vapor trails of sounding rockets." -- 119.31.126.66 (talk) 15:57, 2 January 2011 (UTC)[reply]